4,266 reputation
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visits member for 2 years, 2 months
seen 29 mins ago

I was born to answer lhfs.


Mar
19
accepted Prove that $\rm area(\triangle ABE) = area (ABCD)$
Mar
19
asked Prove that $\rm area(\triangle ABE) = area (ABCD)$
Mar
14
awarded  Nice Answer
Mar
5
answered if x^2 + 2x - 3 >= 0 then (x <= -3) V (x >= 1)
Mar
1
comment What should be added to $x^4 + 2x^3 - 2x^2 + x - 1$ to make it exactly divisible by $x^2 + 2x - 3$?
@HenningMakholm I'm a ninth grader from the same country as Mayank is, and we are taught polynomial division in the ninth grade.
Feb
17
answered Less than or equal sign
Feb
8
awarded  Nice Answer
Feb
3
comment Pre-Calculus Vector Problem.
Hello! If you are reading my answer, please note that I posted it a little late. The problem has already been solved, but I just wanted to add my two cents here.
Feb
3
answered Pre-Calculus Vector Problem.
Feb
3
comment Formula help with this equation
@Mico: Yes, that is correct! Still, might be useful to point out.
Feb
3
comment Formula help with this equation
OP may have meant $(x - 1)^3$. Writing $(x - 1)3$ instead of $3(x - 1)$ is at least not used widely.
Jan
3
awarded  Necromancer
Dec
7
reviewed Approve suggested edit on How can I solve $\frac{2x}{\sqrt{1-x^2}}=0$
Dec
6
answered Logarithm / exponential equation, not sure what to make of this, (simple)
Nov
23
awarded  Nice Answer
Oct
20
awarded  Nice Answer
Oct
20
accepted $\cot\theta + \tan \theta = x$ and $\sec \theta - \cos \theta = y$, evaluate $\left(x^2 y + xy^2\right)^{2/3}$
Oct
20
asked $\cot\theta + \tan \theta = x$ and $\sec \theta - \cos \theta = y$, evaluate $\left(x^2 y + xy^2\right)^{2/3}$
Jul
28
awarded  Necromancer
Jun
24
awarded  Yearling