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| bio | website | |
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| location | ||
| age | ||
| visits | member for | 11 months |
| seen | May 10 at 18:28 | |
| stats | profile views | 12 |
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Feb 21 |
awarded | Scholar |
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Feb 21 |
accepted | How can the Cartan-Weyl basis of su(2) be a basis if it does not consist of antihermitian operators? |
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Feb 21 |
comment |
How can the Cartan-Weyl basis of su(2) be a basis if it does not consist of antihermitian operators? Thanks, Eric and Jyrki. I guess the most important thing to remember is that "... the root vectors Lie in the complexified algebra. This always happens for semi-simple Lie algebras.". |
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Feb 21 |
awarded | Editor |
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Feb 21 |
revised |
How can the Cartan-Weyl basis of su(2) be a basis if it does not consist of antihermitian operators? fix an inconsequential error |
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Feb 21 |
comment |
How can the Cartan-Weyl basis of su(2) be a basis if it does not consist of antihermitian operators? @JyrkiLahtonen, could you elaborate what you meant by the ladder ops existing only in the complexification of su(2). Concerning the number of dimensions, you are completely right, I was thinking of su(3), I will correct it. |
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Feb 21 |
comment |
How can the Cartan-Weyl basis of su(2) be a basis if it does not consist of antihermitian operators? I am not a mathematician, so please be patient when explaining/correcting any misconceptions that I might have. |
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Feb 21 |
asked | How can the Cartan-Weyl basis of su(2) be a basis if it does not consist of antihermitian operators? |
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Jun 26 |
awarded | Student |
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Jun 26 |
asked | Why does the Gauss-Bonnet theorem apply only to even number of dimensons? |
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Jun 26 |
comment |
How do I show this property of a square matrix is true? Saying the same thing shorter: linear independence of columns is equivalent to determinant different than zero is equivalent to linear independence of rows. |
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Jun 26 |
awarded | Supporter |
