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seen May 6 '13 at 15:15

Could you tell me how to get to the Maths Conference?I am supposed to be doing a lecture in about 20 minutes and my driver is a bit lost.

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Feb
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accepted Value of $ \sum \limits_{k=1}^{81} \frac{1}{\sqrt{k} + \sqrt{k+1}} = \frac{1}{\sqrt{1} + \sqrt{2}} + \cdots + \frac{1}{\sqrt{80} + \sqrt{81}} $?
Feb
22
comment Value of $ \sum \limits_{k=1}^{81} \frac{1}{\sqrt{k} + \sqrt{k+1}} = \frac{1}{\sqrt{1} + \sqrt{2}} + \cdots + \frac{1}{\sqrt{80} + \sqrt{81}} $?
Thanks for your answer Jim.
Feb
22
comment Value of $ \sum \limits_{k=1}^{81} \frac{1}{\sqrt{k} + \sqrt{k+1}} = \frac{1}{\sqrt{1} + \sqrt{2}} + \cdots + \frac{1}{\sqrt{80} + \sqrt{81}} $?
Thanks for the answer.
Feb
22
comment Value of $ \sum \limits_{k=1}^{81} \frac{1}{\sqrt{k} + \sqrt{k+1}} = \frac{1}{\sqrt{1} + \sqrt{2}} + \cdots + \frac{1}{\sqrt{80} + \sqrt{81}} $?
Thanks Muzzlator for your fine answer.
Feb
22
comment Value of $ \sum \limits_{k=1}^{81} \frac{1}{\sqrt{k} + \sqrt{k+1}} = \frac{1}{\sqrt{1} + \sqrt{2}} + \cdots + \frac{1}{\sqrt{80} + \sqrt{81}} $?
@JanDvorak Sorry for the delay in replying to you.Yes, I have got the question right.I double-check things before putting them up on this reputed maths forum.
Feb
22
asked Value of $ \sum \limits_{k=1}^{81} \frac{1}{\sqrt{k} + \sqrt{k+1}} = \frac{1}{\sqrt{1} + \sqrt{2}} + \cdots + \frac{1}{\sqrt{80} + \sqrt{81}} $?
Jan
20
comment How many length n binary numbers have no consecutive zeroes ?Why we get a Fibonacci pattern?
Thanks for answering Rob.I had given up on getting any answers for this.I have no reason to doubt your answer (Your reputation says it all)
Jan
20
comment How many length n binary numbers have no consecutive zeroes ?Why we get a Fibonacci pattern?
@AustinMohr I checked that.It was helpful but still doesn't clear the confusion I am facing, especially about the Fibonacci pattern.Is it OK if I let the question stay?