user4140

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 Feb20 answered Is $a$ in relation to $b$ if and only if $a+b$ congruent to $0$ (mod) transitive. Feb20 answered Prove that $(a,bc)=1$ if and only if $(a,b)=1$ and $(a,c)=1$ Feb20 answered Simple proof exercise recommendation, with full answers Feb20 comment Pigeonhole principle for dominoes. at last a sensible idea. But I was told the solution was neat. Feb20 comment Pigeonhole principle for dominoes. This solution doesn't work, can you fix it? Feb20 comment Pigeonhole principle for dominoes. 4+8+12+2=26, not a multiple of 4 Feb19 comment Pigeonhole principle for dominoes. 4 even numbers need not add up to a multiple of 4 for example 4+4+4+2=14 Feb19 revised Using the laws, show that (A-B)-C is a subset of A-C deleted 1 characters in body Feb19 revised monty hall question with 4 doors added 96 characters in body Feb19 answered Using the laws, show that (A-B)-C is a subset of A-C Feb19 revised Using the laws, show that (A-B)-C is a subset of A-C added 11 characters in body Feb19 comment Using the laws, show that (A-B)-C is a subset of A-C You should make sure that the question is repeated in the body of the question too. Feb19 comment Pigeon hole principle? fixed, I now use the term bin. Feb19 revised Pigeon hole principle? added 16 characters in body Feb19 comment Pigeon hole principle? Oh, ok, ok thanks, i'll fix it after lunch, thanks for input anyways, Feb19 revised Pigeon hole principle? added 1 characters in body Feb19 comment Pigeon hole principle? Which definition? Feb19 comment monty hall question with 4 doors Oh, that's what I asked in second comment, I am assuming he only opens 1 door. Clearly if he opens 2 then it is only 3/4. Feb19 answered Pigeon hole principle? Feb19 comment monty hall question with 4 doors Ok, here is how I think it works: you pick door, then he says wanna switch, and opens an empty door. and you get 1 last chance to pick or stay.