7,545 reputation
1940
bio website
location
age
visits member for 1 year, 10 months
seen 3 hours ago

Apr
1
comment Maximum number of tile possible in 2048 game?
nbunis no, it can't be infinity, to make a 2^n you need two 2^{n-1} and so to make a 2^100 you would need at least 100 spaces....
Apr
1
asked Maximum number of tile possible in 2048 game?
Apr
1
reviewed Approve suggested edit on Need to get X by itself, have to rationalize the denominator
Apr
1
reviewed Approve suggested edit on solve initial value problem (linear differential equation)
Apr
1
accepted Creative easy combinatorics problems.
Mar
26
revised Max Word Size as a Function of Number of Words
added 54 characters in body
Mar
26
comment Max Word Size as a Function of Number of Words
No problem, I adjusted the answer to your variables
Mar
26
answered Max Word Size as a Function of Number of Words
Mar
26
comment Max Word Size as a Function of Number of Words
we need a distibution for length of each word
Mar
24
reviewed Approve suggested edit on Continuous bijection from $\mathbb R-\{0\}$ to $\mathbb R$
Mar
22
answered Digit Factorial Sum?
Mar
22
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
The fact you used a different variable made it clear to me. a=a*b really confused me
Mar
22
accepted Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
Mar
22
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
Ohhhhhh, I finally get it. Thanks.
Mar
21
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
By what formula?
Mar
21
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
@coffeemath can we just go ahead and say $a=(b*a)$ is that legit?
Mar
21
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
I really don't understand it. Could you elaborate please?
Mar
21
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
Why is $((b*a)*b)*(b*a)=b$???
Mar
21
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
what do you mean let $a=b*a$
Mar
21
comment Putnam $\bf 2001$ problem A$\bf 1$ (Binary operation)
yes, the only part I don't get is the second equivalence