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22h
awarded  discrete-mathematics
22h
comment Easiest way of finding a root of permutation?
yeah, but you wrote $(134769)$ instead of $(134679)$ :)
22h
comment Easiest way of finding a root of permutation?
exactly, although the third one should be $(285)(134679)$
22h
comment Easiest way of finding a root of permutation?
you can join any two cycles which have the same size.
23h
comment Easiest way of finding a root of permutation?
well, it possible that $(147)$ and $(258)$ where the same cycle. This would yield $(124578)(396)$ there are another $2$ possibilities depending on which pair of cycles are to be joined into a bigger cycle.
23h
comment What is the integral of $1/(1+x)$
did you try deriving both functions
23h
answered polynomial of $4^\text{th}$ degree, prove
23h
comment Easiest way of finding a root of permutation?
if you square a sycle of length 4 you get two cycles of length two which is what you want. If you square four cycles of length $1$ you get four cycles of length $(1)$ which is not what you want.
23h
revised Easiest way of finding a root of permutation?
added 541 characters in body
1d
answered Easiest way of finding a root of permutation?
1d
comment Prove that if $y>1$, then $\forall M\in\mathbb{R}$, there exists an $N$ in the natural numbers s.t. $n\geq N$ implies $y^n>M$.
Just dropped by to say that inequality is known as Bernoulli's inequality. +1
1d
revised Prove that $x-1$ is a factor of $x^n-1$
edited tags
1d
answered Probability that two items selected from a mixed bag will be of particular sorts
1d
comment Multiples of 3 and 5.
planetmath.org/KummersTheorem
1d
answered If two people temporarily covered the cost of \$20 for the 3rd person by paying \$10 each, how much would the 3rd person owe person 1 and 2?
1d
answered Modular Arithmetic, Pythagorean triples
1d
answered Partitioning elements into sets
1d
comment Factorial formula problem
There are $k!$ ways to permute the elements of $\{1,2,3,4\dots k\}$ and there are $n-k$ ways to permute the elements of $\{k+1,k+2\dots n\}$
1d
comment Multiples of 3 and 5.
Why the downvote?
1d
comment Factorial formula problem
Cutting a student in half yields at most one student if you are very lucky. In most cases the result is zero students