11,943 reputation
21650
bio website
location Monkey Island, OK
age
visits member for 2 years, 2 months
seen 10 hours ago

Hello, I am a freshman at The National Autonomous University of Mexico (UNAM).

My interests are contest problems,elementary number theory, combinatorics, graph theory, linear algebra, group theory, abstract algebra and I have been meaning to learn category theory and matroids.


16h
comment Stair flight problem
the cube roots are squared in the denominator.
1d
revised every Abelian group is a converse lagrange theorem group
added 87 characters in body
1d
accepted every Abelian group is a converse lagrange theorem group
1d
comment every Abelian group is a converse lagrange theorem group
oops, my bad, $p$ should be a prime in the factorization of $n$. Yeah, I made a mistake when typing, is it ok then?
1d
revised every Abelian group is a converse lagrange theorem group
edited title
1d
comment every Abelian group is a converse lagrange theorem group
converse lagrange theorem it means the group has a subgroup of order $n$ for each divisor $n$ of $|G|$
1d
revised every Abelian group is a converse lagrange theorem group
edited body
1d
asked every Abelian group is a converse lagrange theorem group
2d
revised Stair flight problem
added 174 characters in body
2d
revised Stair flight problem
added 174 characters in body
2d
answered Stair flight problem
2d
comment If $G/K\cong H/K$ must $G\cong H$?
yes, this lesson has served me well, in this case these where very easy to understand, however I seem to have some trouble with other examples since I'm taking many of the courses from which the examples come simultaneously.
2d
revised Does $G$ always have a subgroup isomorphic to $G/N$?
deleted 12 characters in body
2d
accepted If $G/K\cong H/K$ must $G\cong H$?
2d
comment Does $G$ always have a subgroup isomorphic to $G/N$?
Haha, sorry Dan, I'm not really sure what I should do, should I find a quotient which gives me an element of order smaller than I could find in the group?
2d
comment If $G/K\cong H/K$ must $G\cong H$?
Thanks, does this have to do with the extension problem?
2d
comment If $G/K\cong H/K$ must $G\cong H$?
oh lol, I can't believe I didn't think of that. since both are abelian $C_2$ is normal to both, also the quotient is of prime order so it is $C_2$ right? thanks.
2d
comment Does $G$ always have a subgroup isomorphic to $G/N$?
thank you, am I correct that there can't be a finite abelian counterexample?
2d
accepted Does $G$ always have a subgroup isomorphic to $G/N$?
2d
comment If $G/K\cong H/K$ must $G\cong H$?
G and H both contain K.