Reputation
28,110
Next tag badge:
359/400 score
260/80 answers
Badges
3 35 87
Impact
~277k people reached

May
17
answered How to prove that $2^{n+2}+3^{2n+1}$ is divisible by 7 using induction?
May
17
revised Induced subgraph with radius rad(G)-1
deleted 1 character in body
May
17
answered Induced subgraph with radius rad(G)-1
May
17
comment Induced subgraph with radius rad(G)-1
Oh ok, then my counterexamples don't work.
May
17
comment Herstein Problem No.7 Page 102
@MattSamuel No need to apologize, it is a good topic to discuss in my opinion.
May
17
comment Induced subgraph with radius rad(G)-1
Where did you find this, I think it is false.
May
17
revised Induced subgraph with radius rad(G)-1
added 21 characters in body
May
17
comment Herstein Problem No.7 Page 102
$Z_5\times S_3$ has $3$ elements of order $2$. $D_{15}$ has $16$ elements of order $2$ and $Z_3\times D_5$ has $6$ elements of order $2$. How can they be isomorphic?
May
17
answered Show that $f(x) = 0$ for all $x \in \mathbb{R}$
May
17
comment Herstein Problem No.7 Page 102
No Matt Samuel, they are four: $Z_{30},Z_5\times S_3,D_{15},Z_3\times D_5$. Good effort though.
May
15
comment Poker Chips function
Oh yeah lol, I extrapolated from a book that used a $52$ deck card. thanks.
May
15
revised Poker Chips function
added 863 characters in body
May
15
answered Poker Chips function
May
14
accepted Theoretical way to prove no positive integer $n$ exists such that $n+3$ and $n^2+3n+3$ are both perfect cubes.
May
14
revised Show that $\sqrt{5} \notin \mathbb{Q}(\sqrt{3})$
added 5 characters in body
May
14
comment Find image and kernel of $\varphi: \mathbb{Z}[x] \to \mathbb{C}$ given by $x \mapsto i$
They are already telling you the image is the Gaussian integers implicitly. Also, saying "consider the homomorphism that maps $x$ to $i$" is meaningless unless you have already seen that such a homomorphism always exists and is unique, I think this is sometimes called the universal property of the ring of polynomials.
May
14
comment Function not satisfying the mean value theorem
It does not satisfy the mean value theorem on $\mathbb R$ because if it did then there would be a point in the interval $[-1,1]$ with derivative zero. Since this does not happen it does not satisfy the mean value theorem.
May
14
answered Function not satisfying the mean value theorem
May
14
awarded  Favorite Question
May
14
answered Show that $\sqrt{5} \notin \mathbb{Q}(\sqrt{3})$