Reputation
31,854
Next tag badge:
92/100 score
39/20 answers
Badges
3 42 93
Newest
 Necromancer
Impact
~320k people reached

Jul
19
comment condition for a group to be abelian
lol, this is a cool problem btw.
Jul
19
comment Why the length of the zigzag curve approximating the circle does not approach the length of the circle?
there are continuous functions that are nowhere differentiable.
Jul
19
comment Why the length of the zigzag curve approximating the circle does not approach the length of the circle?
what derivatives?
Jul
19
accepted Subgroups of $S_n$ with exactly one fixed point for each element all have the same fixed point.
Jul
18
comment Subgroups of $S_n$ with exactly one fixed point for each element all have the same fixed point.
Yeah, I messed up on the statement. Sorry about that.
Jul
18
revised Subgroups of $S_n$ with exactly one fixed point for each element all have the same fixed point.
added 12 characters in body; edited title
Jul
18
revised Subgroups of $S_n$ with exactly one fixed point for each element all have the same fixed point.
edited body
Jul
18
asked Subgroups of $S_n$ with exactly one fixed point for each element all have the same fixed point.
Jul
18
comment An evenly divided $k$ coloring of an $(n,d,\lambda)$ graph leaves one vertex adjacent to all $k$ colors, given $k\lambda \leq d$.
+1, that book is amazing by the way.
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
The family $(2,499999\dots 97)$ is a thing.
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
I'm pretty confident we can find various infinite families.
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
so you just have to solve $za$ is a permutation of $a+z$ for each value of $z$ between $1$ and $20$.
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
clearly one of the numbers must be 20 or smaller.
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
47,2 is another pair.
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
oh ok, gotcha .
Jul
18
comment Pairs with sum and product formed by the same digits but arranged differently
your example doesn't work
Jul
18
comment Application of invariant method
If you can divide by $2$ when $n$ is odd the problem becomes false, you can get to $1$ in $4$ steps: $18\mapsto 9 \mapsto 4\mapsto 2 \mapsto 1$ and then you have an even number of moves left, this lets you get to $96$ and then swap between $96$ and $192$, after $60$ minutes you're at $96$ because $\Omega(1)$ has the same parity as $\Omega(96)$.
Jul
18
revised Application of invariant method
added 2 characters in body
Jul
18
answered Application of invariant method
Jul
18
comment How is this derivative paradox solved?
This problem does not meet with the quality standards.