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  • 4 votes cast
Dec
12
asked Finite differences and conservation law
Jul
8
comment Space-dependent diffusivity and finite-differences
Found the mistake, in the explicit part I used $u_{j+1}-u_j$ instead of $[u_{j+1}-u_{j-1}]/2$!
Jul
8
comment Space-dependent diffusivity and finite-differences
Usually, to test it in the simplest case, I use $D(x)=x$ or $D(x)=1-x$, to see how it behaves going to both boundaries.
Jul
8
asked Space-dependent diffusivity and finite-differences
Jun
5
accepted Multiplying a vector and a matrix's rows
Jun
5
comment Multiplying a vector and a matrix's rows
Could you please explicit that?
Jun
5
asked Multiplying a vector and a matrix's rows
Apr
29
accepted Third-order Linear Parabolic PDE
Apr
29
asked Third-order Linear Parabolic PDE
Nov
7
awarded  Supporter
Oct
25
comment Vectorial derivative
@Nick Could you help me trying to explicit the calculation in components of with the index notation? Because I cannot see it, sorry.
Oct
25
comment Vectorial derivative
Why should I do that, mate?
Oct
25
asked Vectorial derivative
Feb
21
comment Orthogonal Part Operator
$(\boldsymbol{p}\cdot\nabla\boldsymbol{p})_\alpha=p_\beta\partial_\beta p_\alpha$
Feb
21
comment Orthogonal Part Operator
No, I simply meant the application of $P$ to those terms: $P(\boldsymbol{p}\cdot\nabla\boldsymbol{p})$
Feb
21
revised Orthogonal Part Operator
added 3 characters in body
Feb
21
revised Orthogonal Part Operator
added 57 characters in body
Feb
21
comment Orthogonal Part Operator
Yes, I need to be clearer. $\boldsymbol{p}$ is a column vector of $\mathbb R^3$, function of $\boldsymbol{x}$, respect to which the differentiation in $\nabla$ is carried. The $P$ operator is exactly the matrix $P_{\alpha\beta}=\delta_{\alpha\beta}-p_\alpha p_\beta$
Feb
21
asked Orthogonal Part Operator
Jul
3
awarded  Autobiographer