145 reputation
6
bio website youtube.com/zonerarefatte
location San Diego, CA
age 25
visits member for 2 years
seen 4 hours ago

Knowledge and understanding are quite different. Only understanding can lead to being, whereas knowledge is but a passing presence in it. (G.Gurdjieff)


2d
comment Probability of a trajectory in Markov processes
@Did Well, I won't go through what has been said. But, simply, please - do not give anyone lessons about what math.SE is the site for. Or about what is a loss or time or not. I didn't find reading this q&a a loss of time, and there will surely be other people thinking like me. Reading your unexplainably arrogant comment, that was indeed a loss of time and a huge let-down.
Jul
8
comment Space-dependent diffusivity and finite-differences
Found the mistake, in the explicit part I used $u_{j+1}-u_j$ instead of $[u_{j+1}-u_{j-1}]/2$!
Jul
8
comment Space-dependent diffusivity and finite-differences
Usually, to test it in the simplest case, I use $D(x)=x$ or $D(x)=1-x$, to see how it behaves going to both boundaries.
Jul
8
asked Space-dependent diffusivity and finite-differences
Jun
5
accepted Multiplying a vector and a matrix's rows
Jun
5
comment Multiplying a vector and a matrix's rows
Could you please explicit that?
Jun
5
asked Multiplying a vector and a matrix's rows
Apr
29
accepted Third-order Linear Parabolic PDE
Apr
29
asked Third-order Linear Parabolic PDE
Nov
7
awarded  Supporter
Oct
25
comment Vectorial derivative
@Nick Could you help me trying to explicit the calculation in components of with the index notation? Because I cannot see it, sorry.
Oct
25
comment Vectorial derivative
Why should I do that, mate?
Oct
25
asked Vectorial derivative
Oct
17
asked Differential system in cylindical coordinates
Feb
21
comment Orthogonal Part Operator
$(\boldsymbol{p}\cdot\nabla\boldsymbol{p})_\alpha=p_\beta\partial_\beta p_\alpha$
Feb
21
comment Orthogonal Part Operator
No, I simply meant the application of $P$ to those terms: $P(\boldsymbol{p}\cdot\nabla\boldsymbol{p})$
Feb
21
revised Orthogonal Part Operator
added 3 characters in body
Feb
21
revised Orthogonal Part Operator
added 57 characters in body
Feb
21
comment Orthogonal Part Operator
Yes, I need to be clearer. $\boldsymbol{p}$ is a column vector of $\mathbb R^3$, function of $\boldsymbol{x}$, respect to which the differentiation in $\nabla$ is carried. The $P$ operator is exactly the matrix $P_{\alpha\beta}=\delta_{\alpha\beta}-p_\alpha p_\beta$
Feb
21
asked Orthogonal Part Operator