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 Mar 25 answered LOVES+LIVE=THERE. How many “loves” are “there”? Mar 24 comment LOVES+LIVE=THERE. How many “loves” are “there”? and hence I can also say that $S\neq0$. I am so sorry for this mistake. Mar 24 asked LOVES+LIVE=THERE. How many “loves” are “there”? Mar 2 comment Bayes' Theorem: Detection of bomb in a box Thanks for the answer. So, from your answer I take it that it not possible to calculate the probability that is required by me. I can say that it is not possible to calculate $P(d_1|{p_1}^c)$ without knowing the threshold and the distribution. Is that right? Also, does you theory also apply if replace bombs with something more safe( say letters ) and boxes with envelopes? If yes, then what will be threshold ( in that case ) ? Feb 27 revised Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$ deleted 1 characters in body Feb 27 comment Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$ sorry, problem in writing LATEX. It is now rectified. Feb 27 revised Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$ wrote both the functions i.e. $x(t)$ and $t(x)$ Feb 26 comment Bayes' Theorem: Detection of bomb in a box In the problem itself it is mentioned that the bomb is equally likely to be present in any of the three boxes. So,I think that$P(p_i)=\frac{1}{3}$. Also, you are right that $\alpha_i$ is the probability that the bomb is detected, provided it is present in the the box i ( i=1,2,3). $P(d_i)$ is indeed denoting just the detection. So ,when I say $P(d_i|p_i)$, I mean detection when it was present and hence, $P(d_i|p_i)$ = $\alpha_i$. Feb 26 awarded Teacher Feb 26 answered Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$ Feb 26 comment Bayes' Theorem: Detection of bomb in a box The bomb is supposed to be detected, not seen. There might be issues with the detector that it is doing so. It might happen that the bomb is pressure sensitive and opening the box might trigger. So, the bomb is to be detected and it might happen that the detector was unable to detect it. Think of the medical cases where a patient is said to free of a disease when , in fact, he has that disease. Feb 26 revised Bayes' Theorem: Detection of bomb in a box added 10 characters in body Feb 26 comment Bayes' Theorem: Detection of bomb in a box I apologize for the inconvenience. Please free to edit the question to make it more understandable. By the way, what was I unable to convey properly? Feb 26 asked Bayes' Theorem: Detection of bomb in a box Jan 9 accepted Estimate the given sum. Jan 9 comment Estimate the given sum. Thanks for the help. I just didn't consider the asymptotic behavior ( even though I was considering large values of N ). Jan 9 revised Estimate the given sum. edited title Jan 9 asked Estimate the given sum. Dec 17 asked In how many ways ( using only whole numbers ) can we divide 49 into 6 parts so that we can obtain any number between 1 to 49? Dec 12 comment Combinatorics with repetitons Thanks for the answer. Multiset really elucidated the concept. Also , the thought that I presented in my questions ( about total number of permutations when we have many objects but those can be divided into two types ) can be used to understand this concept,yes?