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seen Jul 23 at 21:54

Feb
27
comment Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$
sorry, problem in writing LATEX. It is now rectified.
Feb
27
revised Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$
wrote both the functions i.e. $x(t)$ and $t(x)$
Feb
26
comment Bayes' Theorem: Detection of bomb in a box
In the problem itself it is mentioned that the bomb is equally likely to be present in any of the three boxes. So,I think that$P(p_i)=\frac{1}{3}$. Also, you are right that $\alpha_i$ is the probability that the bomb is detected, provided it is present in the the box i ( i=1,2,3). $P(d_i)$ is indeed denoting just the detection. So ,when I say $P(d_i|p_i)$, I mean detection when it was present and hence, $P(d_i|p_i)$ = $\alpha_i$.
Feb
26
awarded  Teacher
Feb
26
answered Find the solution $x(t)$ satisfying initial value problem $\frac{dx}{dt} = e^x e^t$
Feb
26
comment Bayes' Theorem: Detection of bomb in a box
The bomb is supposed to be detected, not seen. There might be issues with the detector that it is doing so. It might happen that the bomb is pressure sensitive and opening the box might trigger. So, the bomb is to be detected and it might happen that the detector was unable to detect it. Think of the medical cases where a patient is said to free of a disease when , in fact, he has that disease.
Feb
26
revised Bayes' Theorem: Detection of bomb in a box
added 10 characters in body
Feb
26
comment Bayes' Theorem: Detection of bomb in a box
I apologize for the inconvenience. Please free to edit the question to make it more understandable. By the way, what was I unable to convey properly?
Feb
26
asked Bayes' Theorem: Detection of bomb in a box
Jan
9
accepted Estimate the given sum.
Jan
9
comment Estimate the given sum.
Thanks for the help. I just didn't consider the asymptotic behavior ( even though I was considering large values of N ).
Jan
9
revised Estimate the given sum.
edited title
Jan
9
asked Estimate the given sum.
Dec
17
asked In how many ways ( using only whole numbers ) can we divide 49 into 6 parts so that we can obtain any number between 1 to 49?
Dec
12
comment Combinatorics with repetitons
Thanks for the answer. Multiset really elucidated the concept. Also , the thought that I presented in my questions ( about total number of permutations when we have many objects but those can be divided into two types ) can be used to understand this concept,yes?
Dec
12
asked Combinatorics with repetitons
Nov
20
awarded  Supporter
Nov
13
awarded  Scholar
Nov
13
accepted Number of subsets of a set having r elements
Nov
13
asked Number of subsets of a set having r elements