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 1d asked Computing center of an algebra Feb 2 answered Why is the Young symmetrizer non-zero? Feb 1 awarded Popular Question Jan 9 comment Has this equation appeared before? I have accepted your answer, although I haven't verified it in Mathematica yet; by hand I can only verify the special case $a=b=c$. Jan 9 accepted Has this equation appeared before? Jan 8 comment Has this equation appeared before? Reference for the above fact? Is it mathematica again :)? and what is the Galois group for our case (which should be solvable)? Jan 8 comment Has this equation appeared before? Wow!, thanks. How did you factor the degree 8 polynomial? Did you use brute force or a computer program, or did you use any clever technique? Jan 5 comment Character related to a maximal subgroup Yes, so $g\in H$ implies $\xi (g)\ne 0$, that is, elements of $\ker (\xi)$ can not be in $H$. Jan 4 comment Has this equation appeared before? @Tom-Tom: Nope, plane (2D) geometry, though I am more interested in the above algebraic equation. Jan 4 comment Has this equation appeared before? It appeared while I was working with a geometric problem. Jan 4 asked Has this equation appeared before? Jan 4 comment Character related to a maximal subgroup If some element $g$ of $G$ fix every coset, then doesn't it act as identity permutation on the coset space, i.e. $\xi (g)=\mathrm{trace}(id )=|G/H|\ne 0$? Jan 4 comment Character related to a maximal subgroup That's my question, how is $\ker\xi\subseteq H$? Jan 4 comment Character related to a maximal subgroup May be I am missing something, but, isn't $\xi$ is same as $\mathbb{C}[G/H]$ as $G$-module ($G$ acts by permuting the cosets) and so $\ker \xi\subseteq G-H$ (since every element of $G$ other than $H$ moves every coset). Jan 1 comment A matrix defines a self adjoint operator if and only if it is symmetric @Omnomnomnom Both follows from here, the other implication should follow from the fact that $Mx=0$ for all $x$ implies $M=0$, I left this as exercise. Jan 1 revised A matrix defines a self adjoint operator if and only if it is symmetric added 26 characters in body Jan 1 answered A matrix defines a self adjoint operator if and only if it is symmetric Oct 19 awarded Taxonomist Oct 9 comment Dimension of the space of cubic polynomials over $\mathbb{P}^5$ which vanish on the Veronese surface. I am not familiar with this stuff, can you tell me the reference where I can find the algorithm that has been used here. Oct 8 asked Dimension of the space of cubic polynomials over $\mathbb{P}^5$ which vanish on the Veronese surface.