network profile
| bio | website | gplus.to/prosteve037 |
|---|---|---|
| location | NY | |
| age | 20 | |
| visits | member for | 1 year |
| seen | Feb 14 at 2:09 | |
| stats | profile views | 4 |
Learn. Create. Play.
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Dec 16 |
awarded | Supporter |
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Dec 16 |
accepted | Strengthening My Foundation in Mathematics |
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Dec 15 |
awarded | Student |
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Dec 15 |
asked | Strengthening My Foundation in Mathematics |
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Sep 3 |
awarded | Scholar |
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Sep 3 |
accepted | Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables |
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Sep 2 |
comment |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables Awesome. Thanks so much for clearing this up for me! :-) You should answer my question so I can +1 you and mark it as the answer haha |
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Sep 2 |
comment |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables @Rahul Narain - So in other words the constants of proportionality for each statement hold the "opposite" variable as a factor, correct? (ie. $A = m(C)B$ and $A = n(B)C$) |
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Aug 3 |
awarded | Editor |
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Aug 3 |
revised |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables added 679 characters in body |
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Jul 31 |
comment |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables Thanks for the response! I've been reading up on the Combined Gas Law after seeing this post and have come across multiple times that the constants in each of the laws are actually functions dependent on the other variable. In other words, $T \propto P \space\rightarrow\space T = c_1(V)P$ and $T \propto V \space\rightarrow\space T = c_2(P)V$ Will this always be the case though? Will the constants always depend on each other like they do here? |
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Jul 27 |
comment |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables I'm also wondering if there is a geometric intuition behind this, can it be proven using lines and areas? |
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Jul 27 |
comment |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables No worries! Thanks for the quick response. Here are the numbers I used $A = 12$, $B = 3$, and $C = 6$. (Thus $k = 4$ and $m = 2$). How would you determine that $\ell = c(4)(2)$? Will $\ell$ always be proportional to $k$ and $m$? |
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Jul 25 |
comment |
Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables Why do you multiply the two terms for $A$ together? And wouldn't $kmBC = A^2$? |
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Jul 25 |
awarded | Analytical |
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Jul 25 |
asked | Proportional to 2 Separate Variables vs. Proportional to Product of 2 Variables |
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Jun 20 |
asked | Euclidean Geometry in Classical Thought - Used for Realization or Representation? |
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Jun 15 |
awarded | Autobiographer |
