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visits member for 2 years, 9 months
seen 23 hours ago

Jan
18
awarded  Tumbleweed
Jan
14
accepted How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
Jan
14
comment How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
Ahh, that explains quite a lot, now (at least in 1D, but that's enough to convince me for now) it reduces to $e^{-\beta U}\mathcal{L}^* g$! Do you want to post this as an answer so I can mark this question as answered?
Jan
13
revised How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
added case in 1D
Jan
13
revised How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
suggested approach
Jan
13
comment How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
Yes, we are. That's just what I tried, but I'm stuck with said term (added it in the question) and I don't see a way to rescue this ansatz, so I wanted to ask if there'd be a more sophisticated approach.
Jan
13
revised How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
added my current progress
Jan
13
asked How to prove $\mathcal{L}e^{-U}g = e^{-U}\mathcal{L}^*g$ for Fokker-Planck operators
Jan
11
asked Finding a homeomorphism between quadratic polynomials
Dec
13
awarded  Citizen Patrol
Sep
24
awarded  Autobiographer
Sep
21
comment What can I think of the function $F$ that's being used for most(?) explicit first order ODEs?
@"Are there any such sentences in the book? Did the professor say anything at all while writing those formulas?" There aren't any explanations in the book and I couldn't attend the lecture (as well as multivariate calculus which might explain the above problem) because I had to do alternative service. Maybe he said something in the lectures, but my fellow students didn't have a clue either.
Sep
21
comment What can I think of the function $F$ that's being used for most(?) explicit first order ODEs?
Thank you very much! Finally I have an idea of what $F$ looks like! The last equation makes perfectly sense now and the second last the problem reduced to the question why there's an $F$ after $\frac{\Delta F}{\Delta y}$ and not after $\frac{\Delta F}{\Delta t}$, but I guess this has something to do with $y$ being a vector. However, this is not part of the original question anymore.
Sep
21
accepted What can I think of the function $F$ that's being used for most(?) explicit first order ODEs?
Sep
20
comment What can I think of the function $F$ that's being used for most(?) explicit first order ODEs?
That still leaves me without a clue what the last term (and others) means though, isn't there any intuitive explanation what the single arguments are for?
Sep
20
asked What can I think of the function $F$ that's being used for most(?) explicit first order ODEs?
Jul
2
awarded  Curious
Apr
26
accepted Is every invertible matrix over an algebraically closed field diagonalisable?
Apr
23
answered Is every invertible matrix over an algebraically closed field diagonalisable?
Apr
23
comment Is every invertible matrix over an algebraically closed field diagonalisable?
Then I'll just refer to your comment, to close this thread–if you feel like it, you can still post one and of course I'll accept yours then.