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1h
comment Evaluate this limit of inverse trigonometric and radical functions without l'Hospital
@afsmi, $\lim_{u\to0}\dfrac{\arctan u}u=\lim_{y\to0}\dfrac y{\tan y}=1$
4h
comment Evaluate this limit of inverse trigonometric and radical functions without l'Hospital
@Tim, $$a^{1/3}=u, a=u^3, b^{1/3}=v$$ etc.
4h
comment To test convergence of improper integral $ \int_{0}^{\infty} \frac{x\log(x)}{(1+x^2)^2}\, \mathrm dx$
Try with $x=1/y$ or $x=\tan u$
21h
comment Summation of series with binomial coefficients
@ThomasAndrews, Definitely. Thanks
21h
comment Trigonometric Idntities under the condition $A+B+C=π$
@Iaamuseruser, $$4x=\pi-A$$ right $$4(x+y+z)=3\pi-(A+B+C)$$ and $A+B+C=\pi$
21h
comment Solving Trigonometric Equation.
Use mathworld.wolfram.com/ProsthaphaeresisFormulas.html correctly in the Right Hand Side
21h
comment Trigonometric Idntities under the condition $A+B+C=π$
@Iaamuseruser, Are you talking about $\sin2x+\sin2y,$ then see mathworld.wolfram.com/ProsthaphaeresisFormulas.html
22h
comment How do I calculate $\sum_{k=1}^{33}\binom{33}{k} k$
$$k\binom nk=n\binom{n-1}{k-1}$$
23h
comment Evaluate $\sum_{n=1}^{\infty} \frac{n}{n^4+n^2+1}$
@Galc127, Difference of mind & finger. Thanks
1d
comment Prove that $\frac{7}{12}<\ln 2<\frac{5}{6}$ using real analysis
@Helen, Related : math.stackexchange.com/questions/1642783/…
1d
comment Prove that $m\tan (\theta-30°)=n\tan (\theta+120°)$
@SchrodingersCat, The division of $\tan$ as $$\dfrac\sin\cos$$ should ideally be done even before applying Componendo-Dividendo,
1d
comment If $\frac{m+1}{m-1}=\frac{cos(\alpha-\beta)}{sin(\alpha+\beta)}$„ then
@Iaamuseruser, Please find the updated version
1d
comment Evaluate the inverse trigonometric integral
@PankajSinha, What is $\tan(A-B)$ formula?
1d
comment Prove that $m\tan (\theta-30°)=n\tan (\theta+120°)$
Expressing $\tan$ as $\dfrac\sin\cos$ will be more easier, right?
1d
comment Prove that $m\tan (\theta-30°)=n\tan (\theta+120°)$
Are supplying all the homework, here? Btw $$\dfrac{m-n}{m+n}$$ reminds me of brilliant.org/wiki/componendo-and-dividendo
1d
comment Proving $\tan A=\frac{1-\cos B}{\sin B} \;\implies\; \tan 2A=\tan B$
@SchrodingersCat, $B=0$ needs special handling! Otherwise its my own way:)
1d
comment Evaluate the inverse trigonometric integral
@RonGordon, Thanks for your observation.
2d
comment What is the integral value of $\frac{\tan 20^\circ+\tan40^\circ+\tan80^\circ-\tan60^\circ}{\sin40^\circ}$?
@aakankshareddy, Welcome. Hope you have understood my rest two methods.
2d
comment Conditional Proof in Trigonometry
@Iaamuseruser, Coud you follow my steps?
2d
comment Trigonometry Proving
@Iaamuseruser, Set $A=\theta, B=\alpha$ and then $$2u=\theta-\alpha$$