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Jul
26
answered How do you write the following set in predicate form?
Jul
26
answered In a triangle, find the minimum and maximum of $\cos(A-B)\cos(B-C)\cos(C-A)$
Jul
26
comment Polynomial of 11th degree
@anon, What's that unique choice?
Jul
26
comment Polynomial of 11th degree
@MarianoSuárez-Alvarez, I was pointing to the given condition. But, from that $A$ can assume any arbitrary finite scalar value, right?
Jul
26
comment Polynomial of 11th degree
@MarianoSuárez-Alvarez, See any arbitrary finite constant will satisfy the given condition, right?
Jul
26
answered Polynomial of 11th degree
Jul
25
answered Trigonometry question
Jul
25
answered Arithmetic Progression with dynamic common difference
Jul
25
comment New Idea to prove $1+2x+3x^2+\cdots=(1-x)^{-2}$
@daryakhosrotash, See math.stackexchange.com/questions/746388/…
Jul
25
comment Prove that $\alpha + \beta=\frac {\pi}{2}$
How $\cos^2\beta-\sin^2\alpha=\cos(\alpha+\beta)?$
Jul
25
answered Prove that $\alpha + \beta=\frac {\pi}{2}$
Jul
24
comment How many solutions for $(6b)^b\equiv (12b-k)^b\mod p$?
@Kurtul, $$b\equiv0\pmod{p-1}$$ is another set of solutions. $$k\equiv18b\pmod p $$ where $b$ is even is another set
Jul
24
comment Find the $\int \frac{(1-y^2)}{(1+y^2)}dy$
@Kashka, Write $$1-y^2=A+B(1+y^2)$$
Jul
24
answered Find the $\int \frac{(1-y^2)}{(1+y^2)}dy$
Jul
23
comment About the solution of $2^x-x^x=0$
We have $$\left(\dfrac x2\right)^x=1$$
Jul
23
answered Point of intersection of $f(x)=\sin(2x)+\cos(2x)$ and the $x$-axis
Jul
23
answered Show the equation $x^2+(3a-2)x+a(a-1)=0$ has real roots for all values of a∈R and show that $x^2-x+1$ has same sign for all values of x
Jul
23
answered Finding $\frac {a}{b} + \frac {b}{c} + \frac {c}{a}$ where $a, b, c$ are the roots of a cubic equation, without solving the cubic equation itself
Jul
23
comment Prove that $ \tan40° + \sqrt 3 =4 \sin40° $
Related : math.stackexchange.com/questions/1202700/… and math.stackexchange.com/questions/10661/…
Jul
22
comment Finding $\frac {a}{b} + \frac {b}{c} + \frac {c}{a}$ where $a, b, c$ are the roots of a cubic equation, without solving the cubic equation itself
Put $x=2\cos y$