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Sep
14
comment Proving $\lim_{n \rightarrow \infty} \frac{\sum_{r=1}^{n} r^a}{n^{a+1}}=\frac{1}{a+1}$
Related : math.stackexchange.com/questions/478344/… and math.stackexchange.com/questions/469885/…
Sep
14
answered Proving $\lim_{n \rightarrow \infty} \frac{\sum_{r=1}^{n} r^a}{n^{a+1}}=\frac{1}{a+1}$
Sep
14
answered Formula for the floor of $n/2$, to be proved by induction
Sep
14
comment Number theoretic proof that $n\mid\phi(a^n-1)$
math.stackexchange.com/questions/398165/…
Sep
14
comment Computing an indefinite integral
$$\lim_{n\to\infty}P_n(x)=e^x$$
Sep
13
answered Range of inverse trigonometric function
Sep
13
comment Solve the equation $a+b+c=abc$ for $a,b,c\in\mathbb{Z}$
math.stackexchange.com/questions/613105/…
Sep
13
comment Decimal expansion of $kn$ contains only $0,7$ for some $k \in \mathbb{N}$
Related : math.stackexchange.com/questions/164986/…
Sep
13
answered Alternative of finding theta when sin $\theta$ and cos $\theta$ are given
Sep
13
comment $\sin ^{-1}(\cos (40 {}^{\circ}))=50 {}^{\circ}$
Relevant point: en.wikipedia.org/wiki/…
Sep
13
comment Find the integral $\int_{0}^{\frac{\pi}{4}}\frac{\sin{x}\cos{x}}{\sin{x}+\cos{x}}dx$
@user84413, Thanks for your feedback, please find the edited version
Sep
13
revised Find the integral $\int_{0}^{\frac{\pi}{4}}\frac{\sin{x}\cos{x}}{\sin{x}+\cos{x}}dx$
added 22 characters in body
Sep
12
comment Find the integral $\int_{0}^{\frac{\pi}{4}}\frac{\sin{x}\cos{x}}{\sin{x}+\cos{x}}dx$
@chinamath, How about this?
Sep
12
answered Find the integral $\int_{0}^{\frac{\pi}{4}}\frac{\sin{x}\cos{x}}{\sin{x}+\cos{x}}dx$
Sep
12
comment Range of function with limit?
math.stackexchange.com/questions/264504/…
Sep
12
awarded  Enlightened
Sep
12
awarded  Nice Answer
Sep
12
comment Solve the equation: $1+2^x+4^x+8^x+16^x+32^x=3(1+2^x+4^x)$
@ThomasAndrews, en.wikipedia.org/wiki/Indeterminate_form#Indeterminate_form_00
Sep
12
answered Solve the equation: $1+2^x+4^x+8^x+16^x+32^x=3(1+2^x+4^x)$
Sep
12
comment Show that $\max(\mathrm{Re} (\exp(it)\cdot z) = |z| $
$$(a\cos t+b\sin t)^2+(a\sin t-b\cos t)^2=a^2+b^2\implies a\cos t+b\sin t\le\sqrt{a^2+b^2}$$