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4h
comment $\cot^{-1}(x)=\pi+\tan^{-1}(1/x)$ when $x<0$
See math.stackexchange.com/questions/304399/… and math.stackexchange.com/questions/610261/…
4h
answered Simple trigonometrical equations
15h
comment Is $a \sin x + b \sin y \leq \sin(ax + by)$ true?
See math.stackexchange.com/questions/128888/…
15h
comment Simplify $ \csc(65^{\circ} + \theta) - \sec(25^{\circ} - \theta) - \tan(55^{\circ} - \theta) + \cot(35^{\circ} + \theta) $.
@Abhishekstudent, See proofwiki.org/wiki/…
15h
answered How to show this integral (Error function)
15h
comment Simplify $ \csc(65^{\circ} + \theta) - \sec(25^{\circ} - \theta) - \tan(55^{\circ} - \theta) + \cot(35^{\circ} + \theta) $.
@Abhishekstudentm $$65^\circ+\theta+(25^\circ-\theta)=90^\circ\iff65^\circ+\theta=90^\circ-(25 ^\circ-\theta)$$
15h
answered Simplify $ \csc(65^{\circ} + \theta) - \sec(25^{\circ} - \theta) - \tan(55^{\circ} - \theta) + \cot(35^{\circ} + \theta) $.
17h
answered Functions - Trig - Determine
18h
comment limit evaluation calculus I
See math.stackexchange.com/questions/1205475/…
19h
comment Proving a complicated identity
@Unknown,In case you don't know Double Angle Formula, see the alternative method
1d
comment Proving a complicated identity
@ClaudeLeibovici, Thanks. I'm an Introvert:)
1d
revised Proving a complicated identity
added 152 characters in body
1d
answered Proving a complicated identity
1d
answered Which points lie on the prependicular bisector of (-1,-6) and (5,-8)
1d
answered Q: Why is this the limit?
1d
answered Combined arithmetic and geometric progression problem
1d
comment How to find the maximum and minimum of the function $f(x) = \frac{3x}{x^2 -2x + 4}$
Related : math.stackexchange.com/questions/174905/…
1d
answered How to find the maximum and minimum of the function $f(x) = \frac{3x}{x^2 -2x + 4}$
1d
comment Solve $x + y + z = xyz$ such that $x , y , z \neq0$
math.stackexchange.com/questions/613105/…
1d
comment A theoretic question about cosine general solution.
@Meitar, For $\cos x/2=-1/\sqrt2,=-\cos\pi/4=\cos(\pi-\pi/4)\implies x/2=2m\pi\pm(\pi-\pi/4)$