Mark Eichenlaub
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 Nov 21 comment Fourier transform for dummies I'm not sure I understand the question, sorry. What do you mean by having it "work"? I'm not familiar with Mathematica, but in general you will need an infinite number of circles, not just two. Nov 9 awarded Yearling Oct 17 awarded Notable Question Oct 8 awarded Popular Question Jul 22 awarded Popular Question Jul 9 awarded Popular Question Apr 25 awarded Popular Question Jan 4 answered Probability in two throws of $3$ indistinguishable dice Nov 9 awarded Yearling Sep 20 awarded Nice Question Sep 5 awarded Popular Question Jul 12 awarded Nice Question Jul 2 awarded Curious Jun 22 awarded Popular Question Jun 12 awarded Good Question May 22 awarded Popular Question Mar 26 awarded Great Answer Dec 10 accepted Solution to $\frac{\partial G}{\partial t}=(1-s)\left(-k_1G+k_2\frac{\partial G}{\partial s}\right)$ Dec 9 comment Solution to $\frac{\partial G}{\partial t}=(1-s)\left(-k_1G+k_2\frac{\partial G}{\partial s}\right)$ Yes, $s\in \mathbb{R}$ and $t \ge 0$. I'll look up the method of characteristics. Dec 9 revised Solution to $\frac{\partial G}{\partial t}=(1-s)\left(-k_1G+k_2\frac{\partial G}{\partial s}\right)$ added 59 characters in body