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Nov
21
comment Fourier transform for dummies
I'm not sure I understand the question, sorry. What do you mean by having it "work"? I'm not familiar with Mathematica, but in general you will need an infinite number of circles, not just two.
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answered Probability in two throws of $3$ indistinguishable dice
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Dec
10
accepted Solution to $\frac{\partial G}{\partial t}=(1-s)\left(-k_1G+k_2\frac{\partial G}{\partial s}\right)$
Dec
9
comment Solution to $\frac{\partial G}{\partial t}=(1-s)\left(-k_1G+k_2\frac{\partial G}{\partial s}\right)$
Yes, $s\in \mathbb{R}$ and $t \ge 0$. I'll look up the method of characteristics.
Dec
9
revised Solution to $\frac{\partial G}{\partial t}=(1-s)\left(-k_1G+k_2\frac{\partial G}{\partial s}\right)$
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