197 reputation
7
bio website umarjamil.com
location Milan, Italy
age 22
visits member for 2 years, 1 month
seen Feb 10 at 12:15

about me?

I am a working student, fulltime, attending Politecnico di Milano (Milan, Italy). Currently I'm working as Senior Software Developer, but I started when I was 15. I love C#, .NET, Python, Linux and obviously Visual Studio! Sometimes I develop mobile apps for iPhone, iPad and Android.


Jul
2
awarded  Curious
Jan
28
accepted proof of limit for $x \to +\infty = +\infty$
Jan
21
comment proof of limit for $x \to +\infty = +\infty$
thank you, I think I understood.
Jan
21
revised proof of limit for $x \to +\infty = +\infty$
typos
Jan
21
asked proof of limit for $x \to +\infty = +\infty$
Dec
11
accepted Exercise about MacLaurin's polynomial and small-o
Dec
11
comment Exercise about MacLaurin's polynomial and small-o
It would be better if you write it, and I will mark your answer as accepted. Otherwise you'll lose the possibility to get reputation ;-)
Dec
11
comment Exercise about MacLaurin's polynomial and small-o
Thank you! How can I mark this post as answered?
Dec
11
comment Exercise about MacLaurin's polynomial and small-o
Thank you, I finally understood. I'll try to write down what I understood: I know that $x^n*x^k = o(x^n)$ for every $k > 0$. So in this case the lowest power is $x^5$. I ignore the others because when the function gets closer to zero ($x\to0$), their "influence" on the value on the function is "masked" by the value of x^5, because it is by far larger than bigger powers of $x$. Am I right?
Dec
11
comment Exercise about MacLaurin's polynomial and small-o
Sorry I am a bit confused. In the following question (math.stackexchange.com/questions/250926/…) I asked why $x^5 = o(x^2)$ as $x\to0$... and I was told in the comments that $o(f(x))$ means "very smaller than", so as $x\to0$, $x^5$ will definitely be smaller than $x^2$. Can you please elaborate your statement "... is a weaker statement."
Dec
11
comment Exercise about MacLaurin's polynomial and small-o
isn't $x^3o(x^4)=o(x^7)$?
Dec
11
asked Exercise about MacLaurin's polynomial and small-o
Dec
4
comment little-o and its properties
thank you Antonio. I also used wolframalpha to plot various functions. Now I have a visual representation of what's happening.
Dec
4
awarded  Commentator
Dec
4
accepted little-o and its properties
Dec
4
comment little-o and its properties
Ok, I'll try with it and let you know if I have problems understanding something.
Dec
4
comment little-o and its properties
thank you, I already read wikipedia before posting, but I wasn't sure if it listed also the particular cases which are usesful in most cases. My course doesn't include Big-O, so I might get confused reading the definition related to it. Can you please only tell me why the statement I wrote is true? I am unable to imagine a sort of mental representation of what's happening to the function...
Dec
4
asked little-o and its properties
Dec
2
comment second derivative of the inverse function
thank you! it was really that simple! Just a single question: if f(x) = g(x), can I also precisely say that f'(x) = g'(x)? Because you used this property at the second implication...
Dec
2
accepted second derivative of the inverse function