meta user
network profile
| bio | website | divisionbyzero.it |
|---|---|---|
| location | Milan, Italy | |
| age | 21 | |
| visits | member for | 11 months |
| seen | Jan 28 at 17:46 | |
| stats | profile views | 3 |
about me?
I am a student @ Politecnico di Milano (Italy) Currently I'm working as Software Developer, but I got my job when I was 15, the year I became a MCP (Microsoft Certified Professional). I love C#, .NET, Python, Linux and obviously Visual Studio! Sometimes I develop mobile apps for iPhone, iPad and Android.
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Jan 28 |
accepted | proof of limit for $x \to +\infty = +\infty$ |
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Jan 21 |
comment |
proof of limit for $x \to +\infty = +\infty$ thank you, I think I understood. |
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Jan 21 |
revised |
proof of limit for $x \to +\infty = +\infty$ typos |
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Jan 21 |
asked | proof of limit for $x \to +\infty = +\infty$ |
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Dec 11 |
accepted | Exercise about MacLaurin's polynomial and small-o |
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Dec 11 |
comment |
Exercise about MacLaurin's polynomial and small-o It would be better if you write it, and I will mark your answer as accepted. Otherwise you'll lose the possibility to get reputation ;-) |
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Dec 11 |
comment |
Exercise about MacLaurin's polynomial and small-o Thank you! How can I mark this post as answered? |
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Dec 11 |
comment |
Exercise about MacLaurin's polynomial and small-o Thank you, I finally understood. I'll try to write down what I understood: I know that $x^n*x^k = o(x^n)$ for every $k > 0$. So in this case the lowest power is $x^5$. I ignore the others because when the function gets closer to zero ($x\to0$), their "influence" on the value on the function is "masked" by the value of x^5, because it is by far larger than bigger powers of $x$. Am I right? |
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Dec 11 |
comment |
Exercise about MacLaurin's polynomial and small-o Sorry I am a bit confused. In the following question (math.stackexchange.com/questions/250926/…) I asked why $x^5 = o(x^2)$ as $x\to0$... and I was told in the comments that $o(f(x))$ means "very smaller than", so as $x\to0$, $x^5$ will definitely be smaller than $x^2$. Can you please elaborate your statement "... is a weaker statement." |
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Dec 11 |
comment |
Exercise about MacLaurin's polynomial and small-o isn't $x^3o(x^4)=o(x^7)$? |
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Dec 11 |
asked | Exercise about MacLaurin's polynomial and small-o |
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Dec 4 |
comment |
little-o and its properties thank you Antonio. I also used wolframalpha to plot various functions. Now I have a visual representation of what's happening. |
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Dec 4 |
awarded | Commentator |
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Dec 4 |
accepted | little-o and its properties |
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Dec 4 |
comment |
little-o and its properties Ok, I'll try with it and let you know if I have problems understanding something. |
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Dec 4 |
comment |
little-o and its properties thank you, I already read wikipedia before posting, but I wasn't sure if it listed also the particular cases which are usesful in most cases. My course doesn't include Big-O, so I might get confused reading the definition related to it. Can you please only tell me why the statement I wrote is true? I am unable to imagine a sort of mental representation of what's happening to the function... |
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Dec 4 |
asked | little-o and its properties |
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Dec 2 |
comment |
second derivative of the inverse function thank you! it was really that simple! Just a single question: if f(x) = g(x), can I also precisely say that f'(x) = g'(x)? Because you used this property at the second implication... |
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Dec 2 |
accepted | second derivative of the inverse function |
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Dec 2 |
asked | second derivative of the inverse function |
