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Jan
12
answered Find a basis for the subspace $\left\{\begin{bmatrix}x & y \\ z & t\end{bmatrix}, x-y-z = 0\right\}$
Jan
6
comment Derivative of a continuous funtion
Okay, so your approach isn't that different from his, but it's always nice to have several ways to do see it.
Jan
5
comment Derivative of a continuous funtion
I see. Is there an easy way to do that? I would do as Krish did, to show that it's linear, but then it's obvious what the derivative is.
Jan
5
comment Derivative of a continuous funtion
You have to be a bit careful, you also have to show that the limit exists.
Dec
19
awarded  Constituent
Dec
10
awarded  Caucus
Dec
4
answered Concise induction step for proving $\sum_{i=1}^n i^3 = \left( \sum_{i=1}^ni\right)^2$
Aug
25
awarded  Nice Answer
Aug
25
answered Factoring $(x+1)(x+2)(x+3)(x+4)+1$
Jun
11
answered prove that $f(x)=\sum _{n=0}^{\infty}\frac{\cos(nx)}{2^n}$ is continuous
Jun
2
awarded  Yearling
Apr
9
revised Integral of 1/(8+2x^2)
added 1 characters in body
Apr
9
answered Integral of 1/(8+2x^2)
Nov
11
comment Calculate $i ^ {i+1}$ and also $i^{i^{i^{\dots}}}$
Similar question: math.stackexchange.com/questions/191572/…
Sep
29
answered Number of path from $A$ to $B$ in a grid that can be traveled either rightward or upward
Sep
26
comment Rating changes and probability calculations for chess world championship
Not an answer to your question, but you might find it interesting: chessbase.com/Home/TabId/211/PostId/4011007/…
Sep
25
answered A function continuous in both arguments
Sep
17
comment Physical interpretation of $q$-deformation
Thanks, but I have a few questions: So I see there is a difference since in a quantum system we have $[x_i, x_j] = 0$, while we have $ x_ix_j=qx_jx_i$ for $q$-deformation. But why are there no exponentials here (like in your comparison)? Shouldn't there be a physical interpretation of $x_ix_j=qx_jx_i$? If it depends on the situation, I would like to see some references to that. Also, could you please give me references about your answer to my first question?
Sep
14
comment Help with limit $\displaystyle\lim_{t\to 0^{+ }}\sup_{x\in[0, \infty)} |e^{-t^2-2tx}f(x+t)-f(x)|=0$..
Good! You learn more that way :)
Sep
14
answered Help with limit $\displaystyle\lim_{t\to 0^{+ }}\sup_{x\in[0, \infty)} |e^{-t^2-2tx}f(x+t)-f(x)|=0$..