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Oct
25
comment Fourier transform of derivative for the bounded function
Oh, I completely forgot about this question. No, the problem was that $f$ was not entire (that's why I only used Wirtinger differentials). I have managed to strengthen "$f$ is bounded" to "$f$ goes to zero on the infinity" since then, for which the proof is trivial. I should probably close the question now, as I'm not even sure this equality can be proved with my initial conditions.
Jun
2
comment Notation for application of the sequence of integrals
@tomasz: thanks, that's a viable variant.
Jun
2
comment Notation for application of the sequence of integrals
@MichaelHardy: that's why I picked the product sign as a temporary placeholder, until I find something better. Although it works better for differentials, because in that case $\partial x_1 \partial x_2$ is technically a product, while for integrals it is more of a successive application which is written similar to a product. I wish there was some sort of big "A" letter for this...