Barranka
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 Jul 24 revised How to get joint probability from Bernoulli correlation matrix (marginal parameters known) added 61 characters in body Jul 24 asked How to get joint probability from Bernoulli correlation matrix (marginal parameters known) Jul 5 awarded Yearling Dec 19 awarded Constituent Dec 15 awarded Caucus Dec 6 comment Prove by induction that $5^n - 1$ is divisible by $4$. Nice, clear, clean... a good answer indeed! Sep 19 comment A function that creates a partition of values such that the sum is 1 Thank you!!! Do you know is this function has some special name (other than geometric series)? (I know I found it in a book some years ago, but I can't remember the name... or the book) Sep 19 awarded Scholar Sep 19 accepted A function that creates a partition of values such that the sum is 1 Sep 19 revised A function that creates a partition of values such that the sum is 1 added 50 characters in body Sep 19 comment A function that creates a partition of values such that the sum is 1 duh, right! Forgot to write that $k$ is a (deterministic) parameter of the function Sep 19 comment A function that creates a partition of values such that the sum is 1 $k$ is a real number in the interval $(0,1)$ Sep 19 revised A function that creates a partition of values such that the sum is 1 added 94 characters in body Sep 19 awarded Student Sep 19 comment A function that creates a partition of values such that the sum is 1 @Donkey_2009 No, I mean exactly the natural numbers... I'm editing the question to make it more clear Sep 19 asked A function that creates a partition of values such that the sum is 1 Sep 17 comment How can one prove that $e<\pi$? Fast, simple, elegant... Love it! Aug 27 comment math fallacy problem: $-1= (-1)^3 = (-1)^{6/2} = \sqrt{(-1)^6}= 1$? I think that it should be noted that $\sqrt{a^2} = | a |$. So, when you calculate $\sqrt{(-1)^6}$ you are doing something like this: $\sqrt{(-1)^6}=((-1)^2)^\frac{3}{2}=\left(\sqrt{(-1)^2}\right)^3=(|-1|)^3=1$ May 13 awarded Caucus Apr 10 comment How can I prove that $xy\leq x^2+y^2$? Quite an elegant hint!