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seen Feb 9 at 22:36

Dec
5
accepted Is $20+k^2\not\equiv4(\text{mod}~7)$ for all $k\geq0$?
Dec
5
awarded  Custodian
Dec
5
reviewed Approve suggested edit on Is $20+k^2\not\equiv4(\text{mod}~7)$ for all $k\geq0$?
Dec
5
comment Is $20+k^2\not\equiv4(\text{mod}~7)$ for all $k\geq0$?
How come adding 2 to $k^2$ makes the statement true, but when you just use $k^2$ the statement is false? (ie. $k^2$ is 0 modulo 7 but 2 + $k^2$ is NOT 0 modulo 7) Why does the 2 have this effect?
Dec
5
asked Is $20+k^2\not\equiv4(\text{mod}~7)$ for all $k\geq0$?
Jul
19
awarded  Popular Question
Jul
18
awarded  Nice Question
Jul
18
awarded  Supporter
Jul
18
comment Proof: For all integers $x$ and $y$, if $x^3+x = y^3+y$ then $x = y$
You could even just say that (x^2+y^2+xy+1) =/= 0, and conclude x-y = 0, and thus x=y, correct? Anyway, thank you for your help!
Jul
18
accepted Proof: For all integers $x$ and $y$, if $x^3+x = y^3+y$ then $x = y$
Jul
18
asked Proof: For all integers $x$ and $y$, if $x^3+x = y^3+y$ then $x = y$
May
31
awarded  Scholar
May
31
accepted How to simplify this rational expression?
May
30
awarded  Student
May
30
asked How to simplify this rational expression?