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location Paris, France
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1d
comment Basic question about conditional expectation
Yes of course! Thx
1d
accepted Basic question about conditional expectation
1d
asked Basic question about conditional expectation
2d
comment Why a Brownian motion and a Poisson process defined at the same probability space are automatically independent?
@saz As soon I have time I'll add the theorem statement and make it clear. Thanks
Aug
27
asked Why a Brownian motion and a Poisson process defined at the same probability space are automatically independent?
Jul
17
awarded  Notable Question
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jul
1
revised Why $\widetilde m = argmin_{m \in \mathcal P(X)} E[m]$ implies $\widetilde m (\arg \min \frac{\delta E}{\delta m}[\widetilde m]) =1$?
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Jul
1
revised Why $\widetilde m = argmin_{m \in \mathcal P(X)} E[m]$ implies $\widetilde m (\arg \min \frac{\delta E}{\delta m}[\widetilde m]) =1$?
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Jun
30
comment Solving $ \inf \left\{ F[\nu] : \nu \in L^2 , \nu \geq 0, \int _0 ^1 \nu=1\right\}$
@Thisismuchhealthier. There is no additional conditions about $\phi$. Please see my idea for approach the optimality condition satisfied by $nu$.
Jun
30
answered Solving $ \inf \left\{ F[\nu] : \nu \in L^2 , \nu \geq 0, \int _0 ^1 \nu=1\right\}$
Jun
30
comment Why $\widetilde m = argmin_{m \in \mathcal P(X)} E[m]$ implies $\widetilde m (\arg \min \frac{\delta E}{\delta m}[\widetilde m]) =1$?
If you are voting down could you at least let a comment to let me know your critics please ? Thanks in advance
Jun
30
revised Why $\widetilde m = argmin_{m \in \mathcal P(X)} E[m]$ implies $\widetilde m (\arg \min \frac{\delta E}{\delta m}[\widetilde m]) =1$?
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Jun
30
asked Why $\widetilde m = argmin_{m \in \mathcal P(X)} E[m]$ implies $\widetilde m (\arg \min \frac{\delta E}{\delta m}[\widetilde m]) =1$?
Jun
30
revised Why the space of probability measures is a subset of the measure space
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Jun
30
revised Why the space of probability measures is a subset of the measure space
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Jun
30
comment Why the space of probability measures is a subset of the measure space
@mookid You'r right mookid I forgot $\phi \geq 0$ Thank you!
Jun
30
asked Why the space of probability measures is a subset of the measure space
Jun
30
revised Solving $ \inf \left\{ F[\nu] : \nu \in L^2 , \nu \geq 0, \int _0 ^1 \nu=1\right\}$
added 102 characters in body