Chris's sis the artist
Reputation
Top tag
Next privilege 20,000 Rep.
Access 'trusted user' tools
3 40 160
Impact
~242k people reached

# 17,335 Reputation

75 yesterday
 +25 19:24 5 events Not the toughest integral, not the easiest one +25 / -2 22:59 6 events About the integral $\int_{-1}^1 \frac{1}{\pi^2+(2 \operatorname{arctanh}(x))^2} \, dx=\frac{1}{6}$ +10 20:52 upvote Proving $\int_{0}^{\infty} \mathrm{e}^{-x^2} dx = \dfrac{\sqrt \pi}{2}$ +5 23:33 upvote Evaluation of $\int_0^1 \frac{\log^2(1+x)}{x} \ dx$ +5 22:59 upvote Evaluating the integral $\int_1^{\infty} \int_1^{\infty} \frac{\Gamma(x+1)\Gamma(y+1)}{x y \Gamma(x+y+2)} \ dx \ dy$ +5 18:13 upvote A nicer closed form? $\int_0^1 \frac{\log (x) \log \left(x^2-x+1\right)}{x^2-x+2} \, dx$ +2 09:18 accept Not the toughest integral, not the easiest one
24 2 days ago
 +10 15:17 2 events Calculating in closed form $\int_0^{\infty} \frac{\text{PolyLog}^{(1,0)}(1,-x)}{1+x^2} \, dx$ +5 21:14 upvote Calculating in closed form $\int_0^1 \log(x)\left(\frac{\operatorname{Li}_2\left( x \right)}{\sqrt{1-x^2}}\right)^2 \,dx$ +5 11:57 upvote Conjecturing the closed form $\frac{\pi ^2}{8}-\frac{\pi ^2}{8 \sqrt{2}}+\frac{\pi \log (2)}{4 \sqrt{2}}$ +10 / -6 23:41 5 events Not the toughest integral, not the easiest one
38 Jul 27
 +10 23:35 upvote The last digit of $2^{2006}$ +10 15:02 upvote Evaluate $\int_0^1{\frac{y}{\sqrt{y(1-y)}}dy}$ +5 23:41 upvote The closed form of $\int_0^{\pi/4}\frac{\log(1-x) \tan^2(x)}{1-x\tan^2(x)} \ dx$ +5 23:34 upvote Calculating in closed form $\int_0^{\infty} \frac{\text{PolyLog}^{(1,0)}(1,-x)}{1+x^2} \, dx$ +5 22:27 upvote Evaluation of $\int_0^1 \frac{\log^2(1+x)}{x} \ dx$ +5 / -2 12:12 2 events A nicer closed form? $\int_0^1 \frac{\log (x) \log \left(x^2-x+1\right)}{x^2-x+2} \, dx$
15 Jul 26
-1 Jul 25
-275 Jul 24
57 Jul 23
42 Jul 22
5 Jul 21
10 Jul 19
30 Jul 18
23 Jul 16
25 Jul 15
43 Jul 13
40 Jul 12
5 Jul 11
5 Jul 9
42 Jul 8
5 Jul 7
28 Jul 6
5 Jul 5
2 Jul 2
60 Jul 1
93 Jun 30
15 Jun 29
50 Jun 28
10 Jun 27
11 Jun 26
10 Jun 25
5 Jun 24