Shane Hsu
Reputation
Next privilege 250 Rep.
 Sep24 awarded Autobiographer Oct19 asked Minimize $ab+bc+ca$ under three second degree constraints Sep29 comment Am I missing anything when doing this taylor expansion? @njguliyev I'll go kill myself, I'm sorry for posting stupid question here. You wanna post it as an answer or delete it? Sep29 asked Am I missing anything when doing this taylor expansion? Sep22 comment How to define “closer to proportion” I see. Thanks a lot! Sep19 awarded Scholar Sep19 comment How to define “closer to proportion” So the idea is to turn my proportion into vector for calculation. And use Uniform Norm? Sep19 accepted How to define “closer to proportion” Sep19 comment How to define “closer to proportion” @copper.hat sum of absolute difference, I will think about that. But how? For example 1 : 3 : 5 and 3 : 4 : 5, one can say their absolute difference is 2 + 1 + 0 = 3 but if we take 1 : 3 : 5 and multiply it by 4/3, we get 4/3 : 4 : 20/3, and their difference will become 5/3 + 0 + 5/3 = 10 / 3, a bit larger than 3. So there will be cases where there are different difference for two proportions. Sep19 asked How to define “closer to proportion” Jan2 awarded Commentator Jan2 comment Why is $ab+bc+ac = 0$ in some situation? @RossMillikan Well, thanks anyway. Jan2 comment Why is $ab+bc+ac = 0$ in some situation? @RossMillikan That's what I mean by "Hell, it's still wrong" I mean my calculation is correct, but it only happens in VERY VERY special situation. So, yes, the idea is wrong. Jan2 awarded Citizen Patrol Jan2 comment Why is $ab+bc+ac = 0$ in some situation? @RossMillikan But hell, it's still wrong, and I think the question itself is not constructive. LOL Jan2 comment Why is $ab+bc+ac = 0$ in some situation? @RossMillikan Here's where I think I am right about organizing it: $(a+b-c)^2 = a^2+b^2+c^2+2ab-2bc-2ac$ And $2m^2n^2-2c^2=2ab-2bc-2ac$ I can simply substitute it. $(a+b-c)^2 = a^2+b^2+c^2+2m^2n^2-2c^2$ And here you go, $2m^2n^2-2c^2$ should be zero, which means $2ab-2bc-2ac$ should also be zero. Jan2 comment Why is $ab+bc+ac = 0$ in some situation? I think I should start to put this under trash. Jan2 comment Why is $ab+bc+ac = 0$ in some situation? ALL: I think I should consider putting this under CS, and simply ask: How to do this without overflow. THOUGH $a = MAX$, $b = MAX$, $c = MAX$, and $\sqrt{a^2 + b^2 + c^2} > MAX$ Jan2 comment Why is $ab+bc+ac = 0$ in some situation? @Cocopuffs Ya, I really want to say it's a false positive. But, since I can't. You win? The problem still remain though, why is it correct under some condition? Jan2 revised Why is $ab+bc+ac = 0$ in some situation? added 203 characters in body