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  • 0 posts edited
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  • 41 votes cast
Nov
22
awarded  Popular Question
Nov
13
awarded  Popular Question
Sep
13
accepted Software to easily draw 3d plots from functions
Sep
13
comment Software to easily draw 3d plots from functions
it's funny, but as far as I remember, I actually resorted to GeoGebra in that situation, it is now installed on my desktop
Jul
23
awarded  Notable Question
Feb
22
awarded  Popular Question
Feb
4
accepted Does a complex number multiplication have a geometric representation and why?
Feb
4
comment Does a complex number multiplication have a geometric representation and why?
okay, thank you, so I've understood that the statement that a complex number can be represented by a vector is incorrect. Please correct me, if I'm wrong
Feb
4
asked Does a complex number multiplication have a geometric representation and why?
Dec
15
awarded  Caucus
Aug
13
accepted How to find a basis of an image of a linear transformation?
Aug
12
comment How to find a basis of an image of a linear transformation?
@BenWest thanks to you and André Nicolas, now it seems clear to me.
Aug
12
revised How to find a basis of an image of a linear transformation?
edited title
Aug
12
comment How to find a basis of an image of a linear transformation?
could you please provide an example?
Aug
12
asked How to find a basis of an image of a linear transformation?
Aug
1
accepted reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
Jul
31
revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
globally changes $\sin{\alpha}^2$ to $\sin^2{\alpha}$ and the same thing for cos
Jul
30
comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
thank you, but the main confusing thing was why I was not able to get the correct coordinates of transformed system's origin.
Jul
30
answered reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
Jul
29
comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
sorry, but I missed the point. Could you please detail how can I get the right answer (that the given equation is an equation of a hyperbola, which is rotated and shifted to the point (-1,2))?