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 Feb22 awarded Popular Question Feb4 accepted Does a complex number multiplication have a geometric representation and why? Feb4 comment Does a complex number multiplication have a geometric representation and why? okay, thank you, so I've understood that the statement that a complex number can be represented by a vector is incorrect. Please correct me, if I'm wrong Feb4 asked Does a complex number multiplication have a geometric representation and why? Dec15 awarded Caucus Aug13 accepted How to find a basis of an image of a linear transformation? Aug12 comment How to find a basis of an image of a linear transformation? @BenWest thanks to you and André Nicolas, now it seems clear to me. Aug12 revised How to find a basis of an image of a linear transformation? edited title Aug12 comment How to find a basis of an image of a linear transformation? could you please provide an example? Aug12 asked How to find a basis of an image of a linear transformation? Aug1 accepted reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve Jul31 revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve globally changes $\sin{\alpha}^2$ to $\sin^2{\alpha}$ and the same thing for cos Jul30 comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve thank you, but the main confusing thing was why I was not able to get the correct coordinates of transformed system's origin. Jul30 answered reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve Jul29 comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve sorry, but I missed the point. Could you please detail how can I get the right answer (that the given equation is an equation of a hyperbola, which is rotated and shifted to the point (-1,2))? Jul29 revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve rollback in order to undo last edit Jul29 revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve added 199 characters in body Jul29 comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve thank you, I did not know about this way. I'll try it asap. Jul29 revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve added 10 characters in body Jul29 asked reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve