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  • 0 posts edited
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  • 40 votes cast
Jul
23
awarded  Notable Question
Feb
22
awarded  Popular Question
Feb
4
accepted Does a complex number multiplication have a geometric representation and why?
Feb
4
comment Does a complex number multiplication have a geometric representation and why?
okay, thank you, so I've understood that the statement that a complex number can be represented by a vector is incorrect. Please correct me, if I'm wrong
Feb
4
asked Does a complex number multiplication have a geometric representation and why?
Dec
15
awarded  Caucus
Aug
13
accepted How to find a basis of an image of a linear transformation?
Aug
12
comment How to find a basis of an image of a linear transformation?
@BenWest thanks to you and André Nicolas, now it seems clear to me.
Aug
12
revised How to find a basis of an image of a linear transformation?
edited title
Aug
12
comment How to find a basis of an image of a linear transformation?
could you please provide an example?
Aug
12
asked How to find a basis of an image of a linear transformation?
Aug
1
accepted reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
Jul
31
revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
globally changes $\sin{\alpha}^2$ to $\sin^2{\alpha}$ and the same thing for cos
Jul
30
comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
thank you, but the main confusing thing was why I was not able to get the correct coordinates of transformed system's origin.
Jul
30
answered reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
Jul
29
comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
sorry, but I missed the point. Could you please detail how can I get the right answer (that the given equation is an equation of a hyperbola, which is rotated and shifted to the point (-1,2))?
Jul
29
revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
rollback in order to undo last edit
Jul
29
revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
added 199 characters in body
Jul
29
comment reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
thank you, I did not know about this way. I'll try it asap.
Jul
29
revised reduction of $6xy + 8 y^2 -12x-26y + 11 = 0$ to canonical one of a second-order curve
added 10 characters in body