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Nov
30
comment How to find the inverse of a unit in a polynomial quotient ring.
Notice that $x^3+1$ is actually reducible, and hence the quotient is actually not an integral domain. However, $1+x^2$ is relatively prime to $x^3+1$ and hence has an inverse in the quotient, by the euclidean algorithm.
Nov
30
answered How to find the inverse of a unit in a polynomial quotient ring.
Nov
26
answered Closed subsets of Lindelöf spaces are Lindelöf
Nov
16
revised $A^2−A=0$, where A is a $9×9$ matrix. Then which is true?
added 72 characters in body
Nov
16
revised $A^2−A=0$, where A is a $9×9$ matrix. Then which is true?
added 38 characters in body
Nov
16
comment $A^2−A=0$, where A is a $9×9$ matrix. Then which is true?
Yes, you are right. Thanks.
Nov
16
revised $A^2−A=0$, where A is a $9×9$ matrix. Then which is true?
added 101 characters in body
Nov
16
answered $A^2−A=0$, where A is a $9×9$ matrix. Then which is true?
Nov
15
comment Question about definition of pullback as a smooth bundle map.
Thank you, that was very helpful.
Nov
15
accepted Question about definition of pullback as a smooth bundle map.
Nov
15
answered A question on Intermediate Value Theorem
Nov
15
revised Proving $\cos (z)$ is real for real values of $z$
added 4 characters in body
Nov
15
answered Proving $\cos (z)$ is real for real values of $z$
Nov
15
comment For any function f from a countable subset M of $\mathbb{R}$ there exists a sequence of continuous functions that converges pointwise to f on M.
Since f_n is continuous on $\mathbb{R}$ it is continuous on any subset of $\mathbb{R}$ in the subspace topology.
Nov
15
asked Question about definition of pullback as a smooth bundle map.
Nov
15
revised For any function f from a countable subset M of $\mathbb{R}$ there exists a sequence of continuous functions that converges pointwise to f on M.
deleted 18 characters in body
Nov
15
answered For any function f from a countable subset M of $\mathbb{R}$ there exists a sequence of continuous functions that converges pointwise to f on M.
Nov
14
comment Comparison test, proving divergence
Nice answer but I think your last line should actually be the first thing you say. If $a_n$ does not converge to $0$ then both diverge. WLOG assume $a_n$ converges to $0$. Then we can use the limit comparison test...
Nov
11
comment Proof using Fermat's Little Theorem
Also notice $n^{10}$ is congruent to $1$ mod $11$ iff $11$ does not divide $n$. But if $11$ divides $n$ then the problem is even easier.