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| bio | website | qoqosz.net |
|---|---|---|
| location | Poland | |
| age | 24 | |
| visits | member for | 1 year |
| seen | Mar 29 at 12:10 | |
| stats | profile views | 179 |
I'm just a physics student.
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1d |
awarded | Yearling |
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May 14 |
awarded | Nice Answer |
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Feb 8 |
awarded | Nice Answer |
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Sep 16 |
awarded | Revival |
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Sep 16 |
answered | Find the functions family that satisfies the inequality $\int_0^1 \frac{dx}{1+f^{2}(x)} <\frac{f(1)}{f'{(1)}}$ |
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Aug 20 |
answered | Solving the integral $\int_{0}^{\infty} \frac{\sin{x}}{x} \ dx = \frac{\pi}{2}$? |
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Jul 26 |
comment |
Sum equals integral Thank you for your answer. These references are very helpful. |
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Jul 26 |
accepted | Sum equals integral |
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Jul 26 |
awarded | Nice Question |
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Jul 25 |
awarded | Nice Answer |
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Jul 16 |
comment |
Inequality Related to $\arctan$ function @Fabian except $x = 0$ ;) |
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Jul 16 |
comment |
How do I calculate the limit of this integral? Your question is related to this one: math.stackexchange.com/questions/160248/… |
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Jul 15 |
comment |
Sum equals integral Actually I would be more interested in neat examples rather than general methods for finding such functions. |
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Jul 14 |
comment |
Sum equals integral @RossMillikan If summation of a series would range also from $-\infty$ to $+\infty$ than ${\rm sinc}$ is a nice example. |
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Jul 14 |
asked | Sum equals integral |
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Jul 9 |
comment |
Find the functions family that satisfies the inequality $\int_0^1 \frac{dx}{1+f^{2}(x)} <\frac{f(1)}{f'{(1)}}$ @Mercy it is derivative which is not increasing. |
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Jul 9 |
comment |
Find the functions family that satisfies the inequality $\int_0^1 \frac{dx}{1+f^{2}(x)} <\frac{f(1)}{f'{(1)}}$ Here's my first though: If we assume that: $f'$ is continuous and not increasing; $f'(1) \neq 0$; $f(0) = 0$; $f(1) \ge 0$, than: $$\int_0^1 \frac{f'(x)}{1 + f^2 (x)} \cdot \frac{dx}{f'(x)} \le \frac{\arctan f(1)}{f'(1)} \le \frac{f(1)}{f'(1)}$$ |
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Jun 29 |
revised |
Integral with exp, ln and arccosh Fixed formula look |
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Jun 29 |
suggested | suggested edit on Integral with exp, ln and arccosh |
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Jun 28 |
answered | Solving a complex integral |
