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Nov
7
comment Product of two independent stochastic variables $XY$
I think it is obvious, but there isn't really a standard notation so who knows
Nov
7
comment Product of two independent stochastic variables $XY$
Is that binomial and Poisson?
Nov
7
comment Is there an algorithm to determine whether a series converges?
@Norbert, you should write out $\sin^2 n $ just to avoid the series being understood as $\sin(n^2)$
Nov
7
comment Dr. Math on factoring - mistake?
Yeah I misread the word simultaneous, I'm sorry
Nov
7
comment Dr. Math on factoring - mistake?
@StevenStadnicki The way I understand it, he says that his functions are a counter example to the condition "there will be necessarily at least one complex ...". His function are not a counterexample of that. Perhaps I misinterpreted what was meant.
Nov
7
comment Dr. Math on factoring - mistake?
your $h(x,y)$ has no real zeroes
Nov
7
comment Coefficients in series expansion of $\left(\frac{x}{1-x}\right)^3$
You should add the "^3" to the question's title
Nov
7
answered How to calculate all combinations of string without repeat the same value
Nov
7
comment Initial value problem: Solution blows up conditions
Please consider editing your question with some work you have done and explain where exactly you are stuck
Nov
7
reviewed Reviewed Prove that the centralizer is a normal subgroup.
Nov
7
comment Proof of $\sum_{k=0}^n k \text{Pr}(X=k) = \sum^{n-1}_{k=0} \text{Pr}(X>k) -n \text{Pr}(X>n)$
@Sepehr If you look at it carefully, it only appears once. The second summation is of index $i$, while the inside sum has not $i$, just a $j$. this is why it becomes $j\times P(X=j$) in the second line. Try writing the first two sums in a array, lines being on $j$ and column on $i$. First line sums each line while second sums each column. I'll edit if you can't get it.
Nov
7
comment Expectation of a positive integer?
see this thread math.stackexchange.com/questions/231832/…
Nov
7
revised Proof of $\sum_{k=0}^n k \text{Pr}(X=k) = \sum^{n-1}_{k=0} \text{Pr}(X>k) -n \text{Pr}(X>n)$
added 106 characters in body
Nov
7
comment Proof of $\sum_{k=0}^n k \text{Pr}(X=k) = \sum^{n-1}_{k=0} \text{Pr}(X>k) -n \text{Pr}(X>n)$
I was proving the wrong thing, when I saw your edit :P
Nov
7
answered Proof of $\sum_{k=0}^n k \text{Pr}(X=k) = \sum^{n-1}_{k=0} \text{Pr}(X>k) -n \text{Pr}(X>n)$
Nov
6
revised Where to begin in approaching Stochastic Calculus?
added 2 characters in body
Nov
6
answered Where to begin in approaching Stochastic Calculus?
Nov
6
comment Where to begin in approaching Stochastic Calculus?
What I meant was, what kind of probability have you done
Nov
6
comment Where to begin in approaching Stochastic Calculus?
When you say probability, is it the measure theory approach or the classical one?
Nov
5
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