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revised FC groups with infinite derived subgroup which are not constructed by direct product of finite groups.
edited body
Jun
18
comment Any Help would thanks : Product of continuous and Riemann integrable function
Yes @user....but remember that first you have to prove $\;f\;$ is Riemann integrable (it is almost trivial).
Jun
18
comment Why must a field with a cyclic group of units be finite?
I think I got it now, @JyrkiLahtonen: "since otherwise" means "if $\;char\neq 2\;$ then $\;-1\neq 1\;$ and ...etc. ". Thanks.
Jun
18
comment Integral domain (rings and fields)
Perhaps the easiest and shortest way: we have that $\;\Bbb Z[i]\le\Bbb C\;$ , and since the last one is a field we're done.