# Gastón Burrull

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bio website location Santiago, Chile age 23 member for 1 year, 11 months seen 16 hours ago profile views 754

 1d revised Non simplicity of a group of order $p^{100}q$ given some conditions. added 70 characters in body 1d comment Non simplicity of a group of order $p^{100}q$ given some conditions. To use 2.- we must prove that there are 2 p sylow subgroups (If exists only one we are done) and for each pair of p Sylow subgroups i want to show that intersection is trivial. I dont believe that is true without abelianity. 1d comment Non simplicity of a group of order $p^{100}q$ given some conditions. I did the same in the exam. So probably 1.- is false. For 2.- I dont know how to do, my attempt is proving the hipotesys for 1 to find a normal q-subgroup 1d comment Non simplicity of a group of order $p^{100}q$ given some conditions. My teacher puts a $p$ in the exam, I also think it must be $q$. I think he is wrong. But in 2.- we probably need to find a $q$- Sylow using 1.- 1d asked Non simplicity of a group of order $p^{100}q$ given some conditions. Apr14 accepted $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ Apr7 comment $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ I understand now, I worked in details in your proof without difficulty. Ty. Apr7 comment $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ Ty................. Apr6 comment $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ Im almost sure that $x_i$ has maximal order in $G_{p_i}$. Is true that order of $g$ is the product of all $x_i$ orders? in that case I am right. For complements do you mean that $=\oplus \ldots \oplus$? Apr6 comment $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ I can follow your response unless "we can assume that there is a prime $p$..." What about $G=C_2\times C_{3^2}$? there are distinct primes here. Apr6 comment $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ Why I can assume $p$-group?, I dont understand Apr6 comment $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ Oh, teacher's proof uses it :(. Apr6 asked $g\in G$ maximal order in $G$ abelian then $G=\left\oplus H$ Mar19 awarded Popular Question Jan30 comment Solution Manual for Chapters 13 and 14, Dummit & Foote No I don't since it is incomplete but I could upload most of chapter 13 Jan25 awarded Revival Jan25 comment Solution Manual for Chapters 13 and 14, Dummit & Foote @JamesS.Cook I have done chapter 13 in spanish with my friends Jan19 comment Convergence = “closer and closer” Or any positive strictly decreasing sequence which does not converges to $0$. Jan14 accepted Solution Manual for Chapters 13 and 14, Dummit & Foote Jan14 answered Solution Manual for Chapters 13 and 14, Dummit & Foote