Taylor Martin
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 Apr 12 answered Liouville’s theorem proof question Feb 27 accepted Some Scaling Estimate for Heat Kernel Feb 12 awarded Nice Answer Oct 27 answered Conditional Expectation and Interpretation of Projection of $Y$ Onto $X$ vs. $Y$ onto $L^{2}(\sigma(X))$ Oct 26 revised Conditional Expectation and Interpretation of Projection of $Y$ Onto $X$ vs. $Y$ onto $L^{2}(\sigma(X))$ added 46 characters in body Oct 26 asked Conditional Expectation and Interpretation of Projection of $Y$ Onto $X$ vs. $Y$ onto $L^{2}(\sigma(X))$ Jul 1 comment is intersection of a countable collection of dense, open subsets of a complete metric space also dense in X? May 9 awarded Yearling Apr 26 awarded Popular Question Apr 13 awarded Popular Question Apr 12 answered Show that a Cauchy sequence has a fast-Cauchy subsequence Apr 10 comment $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? No precise meaning, and none is needed really. The point of my answer (the second part anyway) is to view the differentials in the expression as quantities $\delta x$ and $\delta t$ - when they are finite, you get the same form of the expression plus a small error; as you send the quantities closer to $0$, the error disappears, but so do the quantities - you fix this by dividing and examining the ratio (which in turn leads right back to the first interpretation). Thinking of $dx(\cdot)$ as a linear functional of $\delta t$ is likely beyond the scope of the OP's knowledge. Apr 10 comment $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? Correct, so you didn't read it apparently..... Apr 10 comment $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? I don't follow you - did you read the entire response? Apr 10 revised $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? added 105 characters in body Apr 10 revised $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? added 809 characters in body Apr 10 revised $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? added 809 characters in body Apr 10 answered $dx=\frac {dx}{dt}dt$. Why is this equality true and what does it mean? Mar 14 revised Let $M$ be a bounded subset of the space $C_{[a,b]}$. Prove that the set of all functions $F(x)=\int^{x}_{a}f(t)dt$ with $f\in{M}$ compact. added 73 characters in body Mar 14 comment Let $M$ be a bounded subset of the space $C_{[a,b]}$. Prove that the set of all functions $F(x)=\int^{x}_{a}f(t)dt$ with $f\in{M}$ compact. I saw "$M$ compact" in the title and made that assumption, which makes the proof $\int M$ is compact trivial because of the uniform convergence norm. But I see now the assumption is that $M$ is merely bounded.