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| bio | website | sites.google.com/site/… |
|---|---|---|
| location | Fiji | |
| age | 36 | |
| visits | member for | 1 year, 1 month |
| seen | 8 hours ago | |
| stats | profile views | 1,654 |
I'm a lecturer of mathematics at the University of the South Pacific. My research interests are in algebraic topology and metric geometry.
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Jun 12 |
comment |
Quasiorders and their associated partial orders yes, in the sense that a left adjoint, if it exists, is unique up to a natural isomorphism. |
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Jun 12 |
comment |
How to interpret “computable real numbers are not countable, and are complete”? @Steve it is quite clear the article you cite is, hmmmm, not well-founded (if it were it would not need such 'arguments' as "think for a couple of days and ..."). So, perhaps it is best to avoid referring to it in your question since your question is about computable reals. Before you question can be answered, you will need to tell us what does it mean for the computable reals to be computably complete. Once definitions and (oh yes) axioms are set in place, questions can be asked ans (sometimes) answers can be given. |
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Jun 12 |
answered | Quasiorders and their associated partial orders |
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Jun 11 |
awarded | Great Answer |
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Jun 11 |
reviewed | Approve suggested edit on Proof for Dirichlet Function and discontinuous |
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Jun 11 |
reviewed | Leave Open The opposite category of the category of graphs |
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Jun 10 |
awarded | Good Answer |
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Jun 10 |
reviewed | Close Arc Length of a Curve |
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Jun 10 |
comment |
If $f^2$ is differentiable, how pathological can $f$ be? how can you apply the chain rule if you don't know that $f$ is differentiable? |
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Jun 10 |
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If $f^2$ is differentiable, how pathological can $f$ be? such an $f$ is not continuous, but it's assumed in the question that $f$ is continuous. |
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Jun 10 |
reviewed | Approve suggested edit on Maximum Theorem and minimized value function |
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Jun 10 |
reviewed | Close AMGM proving? Help? Read more… |
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Jun 10 |
reviewed | Approve suggested edit on Group representation in MAGMA |
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Jun 10 |
awarded | Nice Answer |
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Jun 10 |
revised |
My sister absolutely refuses to learn math added 231 characters in body |
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Jun 10 |
comment |
My sister absolutely refuses to learn math @Raindrop I once, for a short period of time, was tutoring a 10-11 year old. She was bored to death with the stuff in school. So, I took an orange and started carving shapes into it. She was delighted to find out that all those facts she was told are true are actually false. She then went to the kitchen and came back with all the fruit she could find and experimented with non-Euclidean geometry. You don't necessarily need university textbooks to engage kids. You just need to keep them away from the crap of standard school curricula and books. |
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Jun 10 |
comment |
My sister absolutely refuses to learn math @GregorBruns I can tell you that in my case it was not, simply because I spent very little time in school. Most of what I did since 6th grade was cut school. A lot. I attended less than 10% of the maths classes from 7th grade onwards. |
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Jun 10 |
comment |
My sister absolutely refuses to learn math @Walkerneo before you diagnose your sister with anything, let's take a mathematical approach. People with dyscalculia certainly have problems with mathematics. People who are taught mathematics in a school that follows the standard crappy program and quite likely by a teacher who does not understand the material properly also have problems with mathematics. The percentage of people with dyscalculia is very small. The percentage of bad teachers and crappy curricula is large. What is the probability that a given sister with math difficulties has dyscalculia? (Hint: ask Bayes). |
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Jun 10 |
revised |
My sister absolutely refuses to learn math deleted 1 characters in body |
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Jun 10 |
reviewed | Close How to calculate $Q_n$estimator |
