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location India
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visits member for 2 years, 2 months
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I am not in this earth by chance. I am here for a purpose and that purpose is to grow into a mountain, not to shrink to a grain of sand. Henceforth will I apply all my efforts to become the highest mountain of all and I will strain my potential until it cries for mercy.

The moving power of mathematical invention is not reasoning but imagination.

Augustus De Morgan


Jul
23
reviewed Approve suggested edit on Simplify $ (a^{-2} - b^{-2})/(a^{-1}-b^{-1})$
Jul
14
reviewed Approve suggested edit on Show that $v_1, v_2, \cdots , v_r$ span $R^n$ if and only if $v_1+\alpha *v_2, v_2, \cdots, v_r$ span $R^n$
Jul
2
awarded  Curious
Jul
2
awarded  Inquisitive
Jun
27
comment If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
accepted :) There is a time frame to accept answer.
Jun
27
accepted If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
Jun
27
comment If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
:) Got it. Thanks a ton.
Jun
27
comment If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
Thanks for the answer. Could you please tell me whether my explanation is correct or not?
Jun
27
comment If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
Thanks for the answer.
Jun
27
comment If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
@FrankScience Thank you very much.
Jun
27
comment If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
@GitGud Thank you I understood now. I also want to know whether my explanation is correct?
Jun
27
asked If $Ax = b$ has more than one solution so does $Ax = 0$, where $A$ is $m\times n$ real matrix.
Jun
27
revised Deletion of disc
Corrected spelling mistake
Jun
26
reviewed Approve suggested edit on How to prove that Δy/Δx = f(x+Δx)-f(x) / Δx?
Jun
26
reviewed Approve suggested edit on Definition singular manifold
Jun
25
revised Moore-Penrose pseudoinverse for square matrix
Corrected some grammatical errors
Jun
24
revised When is the equation $Ax = b$ solvable in the integers?
Corrected spelling mistake
Jun
24
revised Given the permutation $\sigma=\left(\begin{array}{ccccc} 1&2&3&4&5\\ 3&1&2&5&4 \end{array}\right)$
Corrected spelling mistakes and Grammatical errors
Jun
2
awarded  Excavator
Jun
2
revised Proving that any finite integral domain is a field.
edited body