| bio | website | math.leidenuniv.nl/~jcommeli |
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| visits | member for | 1 year |
| seen | Nov 21 '12 at 4:11 | |
| stats | profile views | 5 |
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Aug 22 |
awarded | Supporter |
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May 9 |
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Recovering a number from a remainder list @anon Concerning your second comment, the residue of such an $x$ consists of the images under the canonical projections. In some sense they form the defining data of $x$, so yes, it is equivalent to knowing $x$. |
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May 9 |
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Recovering a number from a remainder list @anon Concerning the first comment: I think it is still correct to say that the residues need not determine an integer (exactly because the $x \in \hat{\mathbb{Z}}$ that they determine is not in the image of $\mathbb{Z}$). I might indeed have added the word 'profinite', but I did not want to make it to difficult at first. I added extra theory in the next paragraphs on $p$-adics, so readers should be able to find their way to the deeper explanation. [Finally, yes, I might have written this answer a bit quickly, and it might have been better if I spent more time on it.] |
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May 8 |
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Recovering a number from a remainder list Indeed the map $\mathbb{Z} \to \hat{\mathbb{Z}}$ is injective. But my point is, that a list of residues need not come from an integer (but if it does, then it is uniquely determined). |
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May 8 |
answered | Recovering a number from a remainder list |
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May 8 |
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Principal divisors on a compact Riemann surface Shouldn't the sum in the definition of f(z) be a product? |
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May 8 |
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What are some examples of a mathematical result being counterintuitive? @MichaelHardy Ok, that makes more sense (-; |
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May 8 |
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What are some examples of a mathematical result being counterintuitive? So the one-point space with your favourite topology is counterintuitive? Interesting... |
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May 8 |
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How much is a topological space $X$ determined by the category of sheaves of abelian groups on $X$? To write down something pretty obvious: If you don't put conditions on $X$ and $Y$ you can certainly not conclude that $X$ and $Y$ are homeomorphic if $\mathsf{Sch}_{\mathsf{Ab}}(X)$ and $\mathsf{Sch}_{\mathsf{Ab}}(Y)$ are equivalent. Take two finite spaces with the trivial topology, that have different cardinality. [I think my point is that if you can say something, you will say it about $\mathsf{Open}(X)$ and $\mathsf{Open}(Y)$, since sheaves do not see points, but only opens.] |