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seen Jan 11 at 22:26

Jan
11
revised Prove that there is a symmetric matrix B, such that BX=Y
Latex coding for improved reading
Jan
11
suggested approved edit on Prove that there is a symmetric matrix B, such that BX=Y
Dec
20
awarded  Caucus
Jul
2
awarded  Curious
Mar
11
accepted From a vector to a skew symmetric matrix
Mar
10
awarded  Popular Question
Feb
22
awarded  Suffrage
Oct
18
awarded  Critic
Oct
17
comment Component-free formula for the determinant of a tensor
Instructive answer. I was hoping for something simpler, in a sense that it would require a lighter background.
Oct
17
accepted Component-free formula for the determinant of a tensor
Oct
17
revised Component-free formula for the determinant of a tensor
added 231 characters in body
Oct
17
comment Component-free formula for the determinant of a tensor
@MarianoSuárez-Alvarez $\mathbf{m},\mathbf{n},\mathbf{p}$ being an orthonormal basis of $\mathbb{R}^3$, consider the determinant of $\mathbb{A}=\mathbf{m}\otimes\mathbf{n}+\mathbf{n}\otimes\mathbf{m}+\mathbf{p} \otimes \mathbf{p}$.
Oct
17
comment Component-free formula for the determinant of a tensor
@MarianoSuárez-Alvarez Yes, this is one way to find the determinant for this example. How about a non-singular tensor?
Oct
17
comment Component-free formula for the determinant of a tensor
@Muphrid good point. I want to write $\mathbf{a}$ but I wrote $\mathbf{m}$. The post is corrected.
Oct
17
revised Component-free formula for the determinant of a tensor
edited body
Oct
17
revised Component-free formula for the determinant of a tensor
added 66 characters in body
Oct
17
asked Component-free formula for the determinant of a tensor
Sep
25
revised Tensors: intrinsic versus index notation
deleted 4 characters in body
Aug
26
revised Sketching Domains and Images in Complex Analysis
Latex improvement
Aug
26
suggested approved edit on Sketching Domains and Images in Complex Analysis