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 Apr3 awarded Notable Question Jan11 revised Prove that there is a symmetric matrix B, such that BX=Y Latex coding for improved reading Jan11 suggested approved edit on Prove that there is a symmetric matrix B, such that BX=Y Dec20 awarded Caucus Jul2 awarded Curious Mar11 accepted From a vector to a skew symmetric matrix Mar10 awarded Popular Question Feb22 awarded Suffrage Oct18 awarded Critic Oct17 comment Component-free formula for the determinant of a tensor Instructive answer. I was hoping for something simpler, in a sense that it would require a lighter background. Oct17 accepted Component-free formula for the determinant of a tensor Oct17 revised Component-free formula for the determinant of a tensor added 231 characters in body Oct17 comment Component-free formula for the determinant of a tensor @MarianoSuárez-Alvarez $\mathbf{m},\mathbf{n},\mathbf{p}$ being an orthonormal basis of $\mathbb{R}^3$, consider the determinant of $\mathbb{A}=\mathbf{m}\otimes\mathbf{n}+\mathbf{n}\otimes\mathbf{m}+\mathbf{p} \otimes \mathbf{p}$. Oct17 comment Component-free formula for the determinant of a tensor @MarianoSuárez-Alvarez Yes, this is one way to find the determinant for this example. How about a non-singular tensor? Oct17 comment Component-free formula for the determinant of a tensor @Muphrid good point. I want to write $\mathbf{a}$ but I wrote $\mathbf{m}$. The post is corrected. Oct17 revised Component-free formula for the determinant of a tensor edited body Oct17 revised Component-free formula for the determinant of a tensor added 66 characters in body Oct17 asked Component-free formula for the determinant of a tensor Sep25 revised Tensors: intrinsic versus index notation deleted 4 characters in body Aug26 revised Sketching Domains and Images in Complex Analysis Latex improvement