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 Dec20 awarded Constituent Dec15 awarded Caucus Dec13 awarded Notable Question Oct29 awarded Yearling Jul2 awarded Curious Mar11 accepted Prove that $\bigcup_{n=2}^{\infty} [1/n, 1 - 1/n] = (0, 1)$ Mar11 asked Prove that $\bigcup_{n=2}^{\infty} [1/n, 1 - 1/n] = (0, 1)$ Dec8 awarded Critic Nov28 accepted Solve $z^4 + 4 = 0$ Nov28 comment Solve $z^4 + 4 = 0$ That $e^{-i \pi} = 1$ is exactly what I was missing. I went and tried to blindly solve it without taking that into account. Thank you and Stahl for pointing it out. Nov28 asked Solve $z^4 + 4 = 0$ Oct20 revised Proving $mn = 0$ implies $m = 0$ or $n=0$ for all $m, n \in \mathbb{N}$ using Peano Axioms added 25 characters in body Oct20 accepted Proving $mn = 0$ implies $m = 0$ or $n=0$ for all $m, n \in \mathbb{N}$ using Peano Axioms Oct20 comment Proving $mn = 0$ implies $m = 0$ or $n=0$ for all $m, n \in \mathbb{N}$ using Peano Axioms $m = k^+$ and $n = l^+$ for some $k, l \in \mathbb N$ by the third axiom. That's a nice and straightforward proof. Thank you. Oct20 asked Proving $mn = 0$ implies $m = 0$ or $n=0$ for all $m, n \in \mathbb{N}$ using Peano Axioms Jul11 revised Why is the Fibonacci ratio though a decreasing function, it is alternating and decreasing? Improved formatting Jul11 suggested approved edit on Why is the Fibonacci ratio though a decreasing function, it is alternating and decreasing? Jul3 comment Proof of $A\cap(B\cup C) = (A\cap B)\cup(A\cap C)$ For proofs like this, using the definition of set operations (which are mostly) and using rules of inference always worked for me. Jun18 awarded Popular Question May9 comment Simplify $(p)(\frac{1}{2}(2p-1)^n) + (1-p)(-\frac{1}{2}(2p-1)^n)$ to $\frac{1}{2}(2p-1)^{n+1}$ Um, I guess you're right. Now I know I have to be more careful with signs. I was cancelling out both $p$.