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 Jun 24 awarded Popular Question Jan 23 accepted Why implication ($\phi x \Rightarrow \psi x$) is always true according to Russell? Jan 23 comment Why implication ($\phi x \Rightarrow \psi x$) is always true according to Russell? Hi @PeterSmith. If I understand T(a) = "if a is human, a is mortal" is a PF of the form $\phi x \Rightarrow \psi x$. Now what Russell says is that T(a) is always true and he is not talking about all of the PFs of the form $\phi x \Rightarrow \psi x$. Am I right? Jan 23 asked Why implication ($\phi x \Rightarrow \psi x$) is always true according to Russell? Dec 9 accepted What does Russell mean when he defines the “Posterity… with respect to the immediate predecessor”? Dec 7 awarded Editor Dec 7 revised What does Russell mean when he defines the “Posterity… with respect to the immediate predecessor”? I modified and described my example in two stages Dec 7 awarded Supporter Dec 7 comment What does Russell mean when he defines the “Posterity… with respect to the immediate predecessor”? Am I wrong when I say that 5 belongs to {0,1,2...}?. Now, since 5 belongs to {0,1,2...} which is hereditary, then {0,1,2...} is the posterity of 5. Dec 7 comment What does Russell mean when he defines the “Posterity… with respect to the immediate predecessor”? Thanks @peter. I think that I understand your post, but I still missing something. When Russell says: "all those terms that belong to every hereditary class to which the given number belongs". I need an example. For example given 5. I want to identify the classes that satisfy the definition. After that, identify the members in order to form the posterity. Dec 6 comment What does Russell mean when he defines the “Posterity… with respect to the immediate predecessor”? I understand when you say 0 does not belong to the posterity of 5. Please, tell me how did you find the posterity of 5? Dec 6 asked What does Russell mean when he defines the “Posterity… with respect to the immediate predecessor”? Apr 30 awarded Scholar Apr 30 accepted Proof for the funky trace derivative : $d (\operatorname{trace} (ABA'C))$? Apr 29 comment Proof for the funky trace derivative : $d (\operatorname{trace} (ABA'C))$? Hi leslie. Now, I understand that proof. Your explanations was very clear. I didn't see matrix calculus and I think the matrix notation was confusing me. Thank you so much. Apr 29 awarded Student Apr 29 asked Proof for the funky trace derivative : $d (\operatorname{trace} (ABA'C))$?