# Goober

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 May1 comment The set $\{g^2 | g \in G\}$ in a group $G$@Arturo Problem is I need $g^2$ to not be in $A_4$ May1 comment The set $\{g^2 | g \in G\}$ in a group $G$@Dylan I get back [423] May1 comment The set $\{g^2 | g \in G\}$ in a group $G$@Dylan If I square [423] then I get [432] May1 comment The set $\{g^2 | g \in G\}$ in a group $G$@Dylan [423] is not in $A_4$, therefore I cannot use it as, say $g$ = [423] since $g \in A_4$ May1 comment The set $\{g^2 | g \in G\}$ in a group $G$Yes, but if $g = [123]$ then $g^2 = [132]$, and if $g \in G$ then $g$ does not contain the cycle [423]: tinyurl.com/84x88se Therefore, I shouldn't be allowed to square any cycle that isn't in $A_4$ I would have thought. Or should I choose my G to be $S_4$? May1 comment finding the quadratic irratonality of simple continued fractionsThere is a similar problem where 3 repeats, so let 3 repeat.