petru

less info
meta site favicon meta user | stack exchange network profile network profile
38 reputation
114
bio website
location
age
visits member for 1 year
seen May 17 at 21:11
stats profile views 23

mamadreqju@gmail.com


27 Actions

suggestions reviews revisions comments badges posts accepts all
Oct
3
 awarded  Fanatic
Jul
25
 awarded  Enthusiast
Jul
5
 comment Conditions for differentiation under integral sign
I'm not affraid, I just needed to be sure :-) Thanks!
Jul
5
 comment Conditions for differentiation under integral sign
Thank you, you're obviously right. But if my integration interval was $(-\infty,+\infty)$ – how should I manage that? Define $g(x)$ for $(-\infty,0)$ and $[0,+\infty)$ separately?
Jul
5
 asked Conditions for differentiation under integral sign
Jun
10
 answered Integral of product of exponential function and two complementary error functions (erfc)
Jun
9
 revised Integral of product of exponential function and two complementary error functions (erfc)
edited title
Jun
9
 asked Integral of product of exponential function and two complementary error functions (erfc)
May
28
 revised Evaluating $ \int_{-\infty}^{\infty}x\exp\left(-b^{2}\left(x-c\right)^{2}\right)\mathrm{erf}^{2}\left(a\left(x-d\right)\right)\,\mathrm{d}x $
added 167 characters in body
May
3
 comment Evaluating $ \int_{-\infty}^{\infty}x\exp\left(-b^{2}\left(x-c\right)^{2}\right)\mathrm{erf}^{2}\left(a\left(x-d\right)\right)\,\mathrm{d}x $
Thanks Dilip. I did calculations you suggested but unfortunately I can’t see how this result is supposed to help me. With $c\neq 0$ I still have integrand $\exp\left(-a^2 (-d + x)^2\right) \mathrm{erf}\left(b (x-c)\right) \mathrm{erf}\left(a (x-d)\right)$ and I don’t know how to proceed with it.
May
3
 answered Evaluating $ \int_{-\infty}^{\infty}x\exp\left(-b^{2}\left(x-c\right)^{2}\right)\mathrm{erf}^{2}\left(a\left(x-d\right)\right)\,\mathrm{d}x $
Apr
29
 awarded  Supporter
Apr
29
 accepted Integral with exp and erf
Apr
29
 revised Integral with exp and erf
corrected the right side of the integral, it’s now sqrt(pi)/b instead of sqrt(pi/b)
Apr
29
 comment Integral with exp and erf
Thanks a lot! It explains all I wanted to know. And yes, I made a typo in the first post: it should be $\frac{\sqrt{\pi}}{b}$.
Apr
29
 revised Evaluating $ \int_{-\infty}^{\infty}x\exp\left(-b^{2}\left(x-c\right)^{2}\right)\mathrm{erf}^{2}\left(a\left(x-d\right)\right)\,\mathrm{d}x $
added 2 characters in body
Apr
29
 awarded  Scholar
Apr
29
 answered Evaluating $ \int_{-\infty}^{\infty}x\exp\left(-b^{2}\left(x-c\right)^{2}\right)\mathrm{erf}^{2}\left(a\left(x-d\right)\right)\,\mathrm{d}x $
Apr
29
 revised Integral with exp and erf
added 6 characters in body
Apr
28
 asked Integral with exp and erf
1 2