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seen May 17 at 16:21

Nov
4
comment Why is stable equivalence necessary in topological K-theory?
Hi Ryan, thanks for your clarification, but it's still murky for me. I don't see why $E \cong F \not \Leftrightarrow (E \oplus G) \cong (F \oplus G)$
Nov
3
comment Why is stable equivalence necessary in topological K-theory?
Are you saying that stable equivalence endows isomorphism classes with a formal inverse? That I don't see.
Nov
3
comment Why is stable equivalence necessary in topological K-theory?
Clarified, I hope.
Nov
3
awarded  Editor
Nov
3
revised Why is stable equivalence necessary in topological K-theory?
clarified question
Nov
3
asked Why is stable equivalence necessary in topological K-theory?
Nov
3
awarded  Scholar
Nov
3
awarded  Student
Nov
3
accepted Why are holomorphic functions defined in reference to an open set?
Nov
3
asked Why are holomorphic functions defined in reference to an open set?