balpha

337 reputation

515

bio	website	balpha.de
	location	Berlin, Germany
	age	32
visits	member for	2 years, 10 months
	seen	May 21 at 11:09
stats	profile views	265

My name is Benjamin Dumke-von der Ehe. I am Stack Overflow Valued Associate #00007, which is just a confusing way of saying that I work as a developer for Stack Exchange.

I am @balpha on Twitter. My blog's "about" page explains the origin of my user name.

I am the creator of Unicornify, the service that gives you these lovable creatures:

I also created Lyfe, a small library adding yield-based generators to JavaScript, and Not a Real Question, a little game that's played with data from various Stack Exchange sites.

I sometimes have a strange sense of humor, but I also like to explain things I fix, break, care about, or come up with.

	337 reputation	bio	website	balpha.de	visits	member for	2 years, 10 months
515 badges		location	Berlin, Germany		seen	May 21 at 11:09

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Jul 2	awarded	Excavator
Jul 2	revised	Chance of getting a date work around mathjax bug
Jun 8	awarded	Constituent
Apr 13	awarded	Convention
Aug 8	awarded	Good Answer
Jul 21	awarded	Yearling
Jul 12	comment	A property of subsets of topological spaces Interesting, in that case I'll have to check my original proof for errors. My topology has become quite rusty, so give my some time :)
Jul 10	awarded	Announcer
May 17	awarded	Quorum
Mar 12	revised	A property of subsets of topological spaces typo
Mar 12	comment	A property of subsets of topological spaces @S.L. I expanded my question with some context.
Mar 12	revised	A property of subsets of topological spaces clarify Lebesgue condition
Mar 12	awarded	Nice Question
Mar 12	revised	A property of subsets of topological spaces add some additional information
Mar 8	comment	Factorial of 0 - a convenience? I've always felt comfortable with $0!=1$, because $(n-1)!=\frac{n!}{n}$
Mar 8	comment	A property of subsets of topological spaces @S.L.: Requiring this property of the set of $X$'s isolated points in addition to $X$ satisifying the Lebesgue condition is necessary and sufficient for compactness; that was the reason for defining it. I'm just not sure if this fact is interesting at all; hence the question.
Mar 8	awarded	Promoter
Mar 6	comment	A property of subsets of topological spaces @HennoBrandsma: Actually, "empty interior" is sufficient -- $Y\setminus N$ needs to be finite, not necessarily $X\setminus N$.
Mar 6	awarded	Commentator
Mar 6	comment	A property of subsets of topological spaces @HennoBrandsma: Yes; indeed I used that as an example to show that in general, "relatively finite" sets need not be countable.