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 Apr12 comment Estimating an integral using the Poisson summation formula It's $\sum_{|m| \leq j}f(m)$ in the end, right? Mar15 comment About a generalization of the Riemann-Lebesgue lemma I've edited the question. Mar15 comment About a generalization of the Riemann-Lebesgue lemma PhoemueX, I'm sorry, you're right. I'm trying to replace my first assumption. Yes, it turns out that the Lebesgue differentiation theorem solves the problem. g belongs to $L^1_{loc}$ then, when we take the limit, $g(x)$ will be bounded by M. I can just replace the two assumptions and the result will still hold :) thanks! Feb15 comment Hilbert-Schmidt norm/smooth manifolds Yes, sorry, I forgot to mention that. I'll edit the text. Sep27 comment Surface orientation Yes, the bases are orthonormal. I corrected that :) Thanks. This problem can be found on Montiel, Curves and Surfaces, page 76. Sep3 comment About scalar products on $\mathbb{R}^n$ Done! :) Thanks May29 comment Nilpotent operator / Orthogonal projection You're right, this isn't true under the given conditions. Oct15 comment Representation of $S^{3}$ as the union of two solid tori Thanks, I edited the title and the tag :) Oct4 comment Second countable topological space Thank you, Brian. =] Sep18 comment Smooth Manifolds Thanks, Matt. I corrected it. Sep12 comment Local Isomorphism on Topological Groups I've changed :) Sep12 comment Local Isomorphism on Topological Groups Oh, sorry, I didn't make it clear. When I started to write this post I first put the title of the topic. He talks about generators of a group later in the same topic. Aug19 comment Matrix subsets dimension Sorry, I've put three "n²-1". Actually, there are just two. I didn't understand it too, but this is how it is written =/ May16 comment Basis to a manifold by coordinate balls Is S really contained in B (line 6)? You meant S contained in the image of B via (phi), no? May14 comment Basis to a manifold by coordinate balls I forgot to ask something else... I have to show that there is a coordinate ball in S^n whose closure is equal to all S^n. The open ball of radius 1 is what we're looking for, isn't? May4 comment Equivalent to the Euclidean fifth postulate Thank you. I missed that. Apr29 comment Disconnected space - Disjoint Union Hum... this is an exercise I solved using the other definition. But it's an interesting definition too =] Apr28 comment Disconnected space - Disjoint Union Answering, should V be the union of h[X_i] where i is different from x_0? Apr28 comment Disconnected space - Disjoint Union Oh, how could I let this pass? I just have to expose an homeomorphis for the first implication. I didn't realize that the two (or more) spaces I would need are just those I know from the definition of conectedness of X. Thank you for opening my eyes. Apr28 comment Disconnected space - Disjoint Union @Jay X is a general topological space, I can't assume it's even Hausdorff.