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  • 0 posts edited
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  • 17 votes cast
Jul
21
asked Absolute continuity via maximal operator
Jun
1
accepted About convergence in norm of the Fourier Transform
May
31
comment About convergence in norm of the Fourier Transform
Why does the convergence holds for $g$ in the Schwartz class?
May
29
comment About convergence in norm of the Fourier Transform
Yes, but the convergence here is in norm. I don't see how this solves... :(
May
25
asked About convergence in norm of the Fourier Transform
May
7
revised An entire function that must be a polynomial
added 15 characters in body
May
7
revised An entire function that must be a polynomial
deleted 1 character in body
May
7
comment An entire function that must be a polynomial
I edited the question with the definition that I'm using :)
May
7
revised An entire function that must be a polynomial
added 214 characters in body
May
7
awarded  Informed
May
7
comment An entire function that must be a polynomial
But every function of exponential type zero would have to be constant, which is not true because any polynomial is of exponential type zero.
May
7
asked An entire function that must be a polynomial
May
5
asked ODE with with translated arguments
Apr
20
awarded  Nice Question
Apr
12
comment Estimating an integral using the Poisson summation formula
It's $\sum_{|m| \leq j}f(m)$ in the end, right?
Apr
11
accepted Estimating an integral using the Poisson summation formula
Apr
8
asked Estimating an integral using the Poisson summation formula
Mar
15
comment About a generalization of the Riemann-Lebesgue lemma
I've edited the question.
Mar
15
revised About a generalization of the Riemann-Lebesgue lemma
deleted 59 characters in body
Mar
15
comment About a generalization of the Riemann-Lebesgue lemma
PhoemueX, I'm sorry, you're right. I'm trying to replace my first assumption. Yes, it turns out that the Lebesgue differentiation theorem solves the problem. g belongs to $L^1_{loc}$ then, when we take the limit, $g(x)$ will be bounded by M. I can just replace the two assumptions and the result will still hold :) thanks!